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Vikki [24]
3 years ago
15

Find the area of the circle to the nearest tenth. 8 cm

Mathematics
1 answer:
liraira [26]3 years ago
4 0

Answer:

201.06.................

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Mrs. Nelson has a rectangular flower box that is 5 feet long and 2 feet tall. She wants the width of the box to no more than 5 f
d1i1m1o1n [39]
Volume = length x width x height.
if the width has to be a whole number no more than 5 then the only options for the width is 1, 2, 3, 4, or 5.
V=5x1x2
V=10
V=5x2x2
V=20
V=5x3x2
V=30
V=5x4x2
V=40
V=5x5x2
V=50
the possible volumes are as follows: 10, 20, 30, 40, and 50.
make sure in your answer that you label your volumes so you write ft^3 after every volume answer.

7 0
3 years ago
14.8 divided by 4 then round to the nearest 10th
irina1246 [14]

Answer:

3.7

Step-by-step explanation:

Really just divide and then round it to only one number on the right of the decimal(use a calculator)

7 0
3 years ago
Read 2 more answers
The weights of steers in a herd are distributed normally. The standard deviation is 200lbs and the mean steer weight is 900lbs.
katen-ka-za [31]

Answer:

0.0369

Step-by-step explanation:

normalcdf (1220,1320,900,200) is 0.0369

3 0
2 years ago
A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one
d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855

The probability  that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0
3 years ago
F(x)= 6+ (10/x) what are the inflection points?
mojhsa [17]

Answer:

An inflection point is a point on the graph of a function at which the concavity changes. Points of inflection can occur where the second derivative is zero.    

Step-by-step explanation:

7 0
3 years ago
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