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Luda [366]
3 years ago
10

Estimate the product. Round the first factor to the nearest whole number, round the second factor to the nearest hundred, and th

en multiply.
9 1/6 * 645 3/5

The product is approximately blank.​
Mathematics
2 answers:
AlexFokin [52]3 years ago
4 0

Answer:

5,400.

Step-by-step explanation:

9 1/6 = 9 to the nearest whole number.

645 3/5 = 600 to the nearest hundred.

The produce = 9 * 600 = 5400.

castortr0y [4]3 years ago
3 0

Answer:

  The product is approximately 5400.

Step-by-step explanation:

  9 1/16 rounded to the nearest whole number is 9.

  645 3/5 rounded to the nearest hundred is 600.

Multiplying these values gives a product of 9·600 = 5400.

The product is approximately 5400.

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Is the square root of 40 a rational number or an irrational number?
kkurt [141]
The square root of *40* is an irrational number.
4 0
4 years ago
Can you please help !!!
Nataly [62]
1)5gallons--->10 fish
20 gallons---->(20*10/5)=40

10fish--->5gallons
1fish---->(1*5/10)=0.5 gallons

10--->5
50--->(50*5/10)=25 gallons
5 0
4 years ago
Give an example of a function with both a removable and a non-removable discontinuity.
navik [9.2K]

Answer:

(x+5)(x-3) / (x+5)(x+1)

Step-by-step explanation:

A removeable discontinuity is always found in the denominator of a rational function and is one that can be reduced away with an identical term in the numerator.  It is still, however, a problem because it causes the denominator to equal 0 if filled in with the necessary value of x.  In my function above, the terms (x + 5) in the numerator and denominator can cancel each other out, leaving a hole in your graph at -5 since x doesn't exist at -5, but the x + 1 doesn't have anything to cancel out with, so this will present as a vertical asymptote in your graph at x = -1, a nonremoveable discontinuity.

8 0
3 years ago
PLEASE HELP VERY URGENT!!!!!!!
Ierofanga [76]

Answer:

The correct option is;

C. (1.6, 1.3)

Step-by-step explanation:

Given that at x = 1.5 the y-values of both equations are y = 1.5 and y = 1 respectively

The x-value > The y-value

The difference in the y-values = 1.5 - 1 = 0.5

At x = 1.6 the y-values of both equations are y = 1.2 and y = 1.4 respectively

The x-value > The y-value

The difference in the y-values = 1.2 - 1.4 = -0.2

At x = 1.7 the y-values of both equations are y = 0.9 and y = 1.8 respectively

The x-value > The first y-value and the x-value < the second y-value

The difference in the y-values = 0.9 - 1.8 = 0.9

Therefore, the approximate y-value can be found by taking the average of both y-values when x = 1.6 where the difference in the y-values is least as follows;

Average y-value at x = 1.6 = (1.2 + 1.4)/2 = 1.3

Therefore, the best approximation of the exact solution is (1.6, 1.3)

By calculation, we have;

-3·x + 6 = 4·x - 5

∴ 7·x = 11

x = 11/7 ≈ 1.57

y = 4 × 11/7 - 5 ≈ 1.29

The solution is (1.57, 1.29)

8 0
3 years ago
Verify the identities by working down one side of the identity or the other, or both sides of the identity.
faust18 [17]

Answer: Photo math will do it in 2.5 secon

ds

Step-by-step explanation:

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3 years ago
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