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Illusion [34]
3 years ago
14

What is the area of the triangle in this coordinate plane?

Mathematics
2 answers:
GREYUIT [131]3 years ago
8 0
That is 5,3 because the axis at which it rests is at the y point.
4vir4ik [10]3 years ago
6 0

Answer:

need points

Step-by-step explanation:

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lisov135 [29]

Answer:

Step-by-step explanation:

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5 0
3 years ago
What are these answers?
Inessa05 [86]
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i think this is the answer
7 0
3 years ago
Which is the completely factored form of 12x^3-60x^2+4x-20​
Shkiper50 [21]

Answer:

(12x²+4)(x-5)

Step-by-step explanation:

To factor the expression factor by grouping.

(12x³ - 60x²) + (4x - 20)

12x²(x - 5) 4(x-5)

(12x²+4)(x-5)

6 0
3 years ago
Which equation represents exponential decay? * a y=3^x-4 b y=2(4)^x c y=1/2(3)^x d: y=6(1/3)^x
yuradex [85]

The equation which represents exponential decay is y=6(1/3)^{x}

Given four equations : 1)y=3^{x} -4, 2) y=2(4)^{x}, 3) y=3^{x}/2, 4) y=6(1/3)^{x}.

Equation is relationship between two or more variables expressed in equal to form. Equations of two variables look like ax+by=c. Exponential equation look like a^{x}.

Decay means when x value increases ,the y value decreases.

We haveto put 3 values for x in the equations to check.

1)y=3^{x} -4

put x=0,y=-3

put x=1, y=-1

put x=2, y=5

No,itdoes not represents exponential decay.

2) y=24^{x}

put x=0,y=2

put x=1, y=8

put x=2, y=32

No,it does not represents exponential decay.

3) y=3^{x}/2

put x=0,y=0.5

put x=1, y=1.5

put x=2, y=4.5

No,it does not represents exponential decay.

4)y=6(1/3)^{x}

put x=0,y=6

put x=1, y=2

put x=2, y=0.67

Yes ,it represents exponential decay.

Hence the equation which represents exponential decay is y=6(1/3)^{x}.

Learn more about equations at brainly.com/question/2972832

#SPJ4

4 0
2 years ago
Evan tosses a ball from the roof of a building. The path of the ball can be modelled
DiKsa [7]

Answer:

Please find attached sketch of the path of the ball, having plot area and plot points, created with MS Excel

Step-by-step explanation:

Question;

The equation representing the path of the ball obtained from a similar question posted online are;

h₁ = -4·(t + 1)·(t - 5), h₂ = -4·(t - 2)² + 36, h₃ = -4··t² + 16·t + 20

The above equations represent the same path

The equation, h₁ = -4·(t + 1)·(t - 5), gives the roots of the height function, h(t), used in determining the height of the ball after time <em>t</em>

At (t + 1) = 0 (t = -1) or at (t - 5) = 0 (t = 5), the ball is at ground level

The ball reaches the ground, is at ground level at t = 1, and at t = 5 seconds after being tossed, where h(t) = 0

The equation of the path of the ball in vertex form, y = a·(x - 2)² + k, is h₂ = -4·(t - 2)² + 36, where, by comparison, we have;

The vertex of the ball = The maximum height reached by the ball  = (h, k) = (2, 36)

The coefficient of the quadratic term, t², is negative, therefore, the shape of the parabola is upside down, ∩, shape

The sketch of the path of the ball created with MS Excel, used in plotting the vertex, the initial value and the root points of the parabola, through which the ball passes and joining of the points with a 'smooth' curve is attached

5 0
3 years ago
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