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Triss [41]
3 years ago
8

What is 2 - 8x + x - 5

Mathematics
1 answer:
LuckyWell [14K]3 years ago
6 0
-7x-3 is 2 - 8x + x - 5
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What is 834% expressed as a fraction?
svetoff [14.1K]

Answer:

8.34/1

Step-by-step explanation:

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Find gradient <br><br>xe^y + 4 ln y = x² at (1, 1)​
cricket20 [7]

xe^y+4\ln y=x^2

Differentiate both sides with respect to <em>x</em>, assuming <em>y</em> = <em>y</em>(<em>x</em>).

\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}

\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x

\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

Solve for d<em>y</em>/d<em>x</em> :

e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x

\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}

If <em>y</em> ≠ 0, we can write

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}

At the point (1, 1), the derivative is

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}

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3 years ago
What is the answer to 25/0.5?
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the answer is 40......

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If ∠3 = 46°, then ∠6 =<br> look at image
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Dina invests $600 for 5 years at a rate of 2% per year compound interest.
Aleks [24]

Answer:

The value of this investment at the end of the 5 years is of $662.5.

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Dina invests $600 for 5 years at a rate of 2% per year compound interest.

This means that P = 600, t = 5, r = 0.02, n = 1. Thus

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 600(1 + \frac{0.02}{1})^{t}

A(t) = 600(1.02)^t

Calculate the value of this investment at the end of the 5 years.

This is A(5). So

A(5) = 600(1.02)^5 = 662.5

The value of this investment at the end of the 5 years is of $662.5.

5 0
3 years ago
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