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Rama09 [41]
3 years ago
15

A train leaves at 13.23 and arrives at its destination at 14.05. If the train travelled 31 km, what was it's average speed in km

/h? Give your answer rounded to 1 dp.
Mathematics
1 answer:
mr_godi [17]3 years ago
6 0

Answer:

0.738 km/h

Step-by-step explanation:

It took 42 minutes from takeoff to get to its destination, so when you divide 31/ 42 (42 representing the time and 31 km representing the distance), you get 0.738 km/h

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This question here ?!
Yanka [14]

Answer:

The answer is 3.19, someone irrationally deleted my answer previously.

Step-by-step explanation:

Simply substract 2.95 from 18.90 and you will get 15.95

Divide this by 5 to get the price of each and you will get $3.19 which is the correct answer.

6 0
3 years ago
A cone shaped party hat has a radius of 3 inches and a height of 6.5 inches. Find the number of cubic units that hat occupies?
dexar [7]

Answer:

61.25

Step-by-step explanation:

8 0
3 years ago
GIVING 50 POINTS FOR THE FIRST 2 PEOPLE
pochemuha

Answer:Thanks

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The number of texts per day by students in a class is normally distributed with a 
kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4)  For x < 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

For x > 100:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

Option 5 is incorrect

6)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5

Since 1.5 is between 1 and 2, option 6 is correct

5 0
3 years ago
Geometry <br> Find the degree for each angle in the triangle
tino4ka555 [31]

Answer:

acute

Step-by-step explanation:

3 0
3 years ago
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