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OverLord2011 [107]

3 years ago

5

Small earthworms travel at speeds of about 0.2 centimeters per second. What is this speed in meters per second? 0.0002 meters pe

r second 0.002 meters per second 20 meters per second 200 meters per second

2 answers:

Ahat [919]3 years ago

7 0

Answer: 0.002 meters per second

Step-by-step explanation:

-Dominant- [34]3 years ago

3 0

Answer:

The answer is b.

Step-by-step explanation:

I took the test and got it right.

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imagine that the recipe is doubled and that 4 cups of sugar are used use the unit rate and a to find how much flour is needed to

erica [24]

Answer:

Well, 4 doubled is 8, and with a unit rate it would be 8/1!

Step-by-step explanation:

5 0

3 years ago

To cut a lawn, Allan charges a fee of $15 for his equipment and $8.50 per hour spent cutting a lawn. Taylor charges a fee of $12

777dan777 [17]

Answer:

Step-by-step explanation:

Let y be the total charge and x no of hours spent for cutting the lawn,

Then for Allan we have the equation as

y = 8.50x+15

SInce 15 is the fixed charge and 8.50 is charged per hour we get the above equation for Allan.

Next similarly for Taylor, we have fixed charges 12 and variale 9.25

y =9.25x+12

When Taylor total charges is greater than Allan's total charge

we have 9.25x+12>8.5x+15

Simplify to get

0.75x>3

Or x>4

Whenever x i.e. no of hours exceed 4, Taylor charges will be greater than that of Allan

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=-3%2Fz%2B7%2F4z%3D5%2Fz-25" id="TexFormula1" title="-3/z+7/4z=5/z-25" alt="-3/z+7/4z=5/z-25" a

ycow [4]

Answer:

z = 1/4

Step-by-step explanation:

See attached image

4 0

2 years ago

Read 2 more answers

What is 0.316 in expanded form

Inessa [10]

<span>0.316 in expanded form is= 0.3 + 0.01 + 0.006. </span>

5 0

3 years ago

An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha

natita [175]

Answer:

Step-by-step explanation:

Given that:

Population Mean = 7.1

sample size = 24

Sample mean = 7.3

Standard deviation = 1.0

Level of significance = 0.025

The null hypothesis:

$H_o: \mu = 7.1$

The alternative hypothesis:

$H_a: \mu > 7.1$

This test is right-tailed.

$degree \ of \ freedom= n - 1 \\ \\ degree \ of \ freedom = 24 - 1 \\ \\ degree \ of \ freedom = 23$

Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test $t_c = 2.069$

The test statistics can be computed as:

$t = \dfrac{ \hat X - \mu_o}{\dfrac{s}{\sqrt{n}}}$

$t = \dfrac{ 7.3-7.1}{\dfrac{1}{\sqrt{24}}}$

$t = \dfrac{0.2}{0.204}$

t = 0.980

Decision rule:

Since the calculated value of t is lesser than, i.e t = 0.980 < $t_c = 2.069$ , then we do not reject the null hypothesis.

Conclusion:

We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.

6 0

3 years ago