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Mashcka [7]
3 years ago
11

Select all expressions that are equivalent to 2+y+y+y+y+y+3?

Mathematics
1 answer:
ryzh [129]3 years ago
7 0
I can’t see your choices, but this equation can be simplified to 5y + 5.

If you add the choices as a comment, I’m happy to help more.
You might be interested in
Help!! Please also explain how you got your answer
yuradex [85]

Answer:

y = -½x + 4

Step-by-step explanation:

the line passes point of y-intercept (0, 4) ,

and another point (6, 1)

the slope = (1-4)/(6-0) = (-3)/6 = -½

so the Equation is y = -½x + 4

6 0
3 years ago
Select all the fractions that are equivalent to 30%.
choli [55]
30% is equivalent to 3/10
So any fraction that can be simplified to 3/10.
Another way to to think about it if you multiply 3/10 by any number over it self because that is equivalent to 1.
Like 3/10 * 2/2 =6/20 is also equal to 30%
5 0
4 years ago
write one way or representing the equation of the given line in point-slope form. then write the equation in slope-intercept for
ehidna [41]

Answer:

y + 1 =-\frac{5}{3}(x-1)

y = -\frac{5}{3}x + \frac{2}{3}

Step-by-step explanation:

To write the equation of a line you need a point and a slope. Use the two points given to find the slope.

m = \frac{-1 - 4}{1--2} = \frac{-5}{3}

Substitute m = -5/3 and the point (1,-1) into the point slope form.

y - y_1 = m(x-x_1)\\y --1 = -\frac{5}{3}(x-1)\\y + 1 =-\frac{5}{3}(x-1)

Use the distributive property to convert to slope intercept form.

y + 1 = -\frac{5}{3}x + \frac{5}{3}\\y = -\frac{5}{3}x + \frac{5}{3} - 1\\y = -\frac{5}{3}x + \frac{2}{3}

5 0
3 years ago
Let $\mu$ and $\sigma^2$ denote the mean and variance of the random variable x. determine $e[(x-\mu)/\sigma]$ and $e{[((x-\mu)/\
Nezavi [6.7K]
\mathbb E\left(\dfrac{X-\mu}{\sigma}\right)=\dfrac1\sigma\mathbb E(X)-\dfrac\mu\sigma=\dfrac{\mu-\mu}\sigma=0

\mathbb E\bigg(\left(\dfrac{X-\mu}\sigma\right)^2\bigg)=\dfrac1{\sigma^2}\mathbb E\left(X^2-2\mu X+\mu^2\right)=\dfrac{\mathbb E(X^2)-2\mu\mathbb E(X)+\mu^2}{\sigma^2}
=\dfrac{\mathbb E(X^2)-2\mu^2+\mu^2}{\sigma^2}=\dfrac{\mathbb E(X^2)-\mu^2}{\sigma^2}=\dfrac{\mathbb E(X^2)-\mathbb E(X)^2}{\sigma^2}
=\dfrac{\mathbb V(X)}{\sigma^2}=\dfrac{\sigma^2}{\sigma^2}=1
3 0
4 years ago
What is 2/9 of 18 the calculations too pls! (Fractions)
adell [148]

Answer:

18/9=2 2*2=4

answer is 4

Step-by-step explanation:

3 0
3 years ago
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