Using the asymptote concept, we have that:
- The vertical asymptote is x = 9.
- The horizontal asymptote is y = 3.
- The end behavior is that as
.
<h3>What are the asymptotes of a function f(x)?</h3>
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, the function is:
For the vertical asymptote, we have that:
x - 9 = 0 -> x = 9.
For the horizontal asymptote:
Hence, the end behavior is that as .
More can be learned about asymptotes at brainly.com/question/16948935
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Answer:
a H I o p=0.80 vs. Ha less than 0.80, where P equals the true proportion of All American adults who do not have an emergency fund
Answer:
$44.74
------Work------
6.25 x 5 = 31.25
31.25 + 12.50 = $44.74
Step-by-step explanation:
May I have brainliest?
</3 PureBeauty
Answer:
(d) f(x) = (x − 3)^2(x − 2)(x − 1)
Step-by-step explanation:
In this context, a crossing of the axis at x=p means there is a factor of (x-p). A "touch" of the axis at x=q means there is a factor of (x -q)^2.
A crossing at x=1 and x=2, and a touch at x=3 means the factors are ...
f(x) = (x -1)(x -2)(x -3)^2 . . . . . matches the last choice
Answer:
And we can find the limits in order to consider values as significantly low and high like this:
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
For this case we can consider a value to be significantly low if we have that the z score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is higher tor equal to 2.
For this case we have the mean and the deviation given:
And we can find the limits in order to consider values as significantly low and high like this:
