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2 years ago

Factor the expression: 3x + 6* Please help

Mathematics

2 answers:

attashe74 [19]2 years ago

6 0

Answer:

3(x+2)

Step-by-step explanation:

Misha Larkins [42]2 years ago

6 0

Answer:

3 (x + 2)

Step-by-step explanation:

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shtirl [24]

Answer:

x = –8

Step-by-step explanation:

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2 years ago

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In a right triangle, the sine of an angle is 0.854. what is the cosine of the same angle? there are two possible answers, one po

klemol [59]

Hi,

$\cos(0.854) = 0.656$

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3 years ago

Calculate the area of parallelogram. <br><br>

Nesterboy [21]

Answer:

84. What you did is right.

Step-by-step explanation:

A parallellogram's area is b x h. So the equation is 7 x 12=84.

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3 years ago

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Multiplication in GF(24 ): Compute A(x)B(x) mod P(x) in GF(24 ) using the irreducible polynomial P(x) = x 4 + x + 1, where A(x)

tankabanditka [31]

Answer:

Step-by-step explanation:

hello,

i advice you check the question again if it is GF( $2^{4}$ ) or GF(24). i believe the question should rather be in this form;

multiplication in GF( $2^{4}$ ): Compute A(x)B(x) mod P(x) = $x^{4}$ + $x$ +1, where A(x)= $x^{2}$ +1, and B(x)= $x^{3} + x+1$ .

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)= $(x^{2} +1) (x^{3}+x+1) mod (x^{4}+x+1 ) = (x^{5} +x^{3}+x^{2} ) + (x^{3}+x+1 ) mod (x^{4} + x+1 )$

= $x^{5}+2x^{3} +x^{2} + x + 1 mod(x^{4}+x+1 )$

= $2x^{2} +1$

please note that the division by the modulus above we used

$\frac{x^{5}+2x^{3}+x^{2} +1 }{x^{4}+x+1}= x+\frac{2x^{3} +1}{x^{4}+x+1}$

5 0

2 years ago

What is an explicit formula for the geometric sequence -64,16,-4,1,... where the first term should be f(1).

nirvana33 [79]

Answer:

$a_{n} = -64(-\frac{1}{4})^{n-1}$

it seems like the first term is -64, so lets write the formula accordingly:

a_n = a1(r)^(n-1)

where 'n' is the number of terms

a1 is the first term of the sequence

'r' is the ratio

the ratio is $-\frac{1}{4}$ because -64 * $-\frac{1}{4}$ = 16 and so on...

the explicit formula is :

$a_{n}$ = $-64(-\frac{1}{4} )^{n-1}$

7 0

2 years ago