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OverLord2011 [107]
3 years ago
15

If you had a rubik's cube with 10 little squares on each side, and peeled off the outer layer, how many little cubes would you e

nd up with?
Mathematics
2 answers:
Pachacha [2.7K]3 years ago
7 0
There is 6 sides in a cube, multiplying we get the number of squares:
6*10 = 60 little squares. 
Peeling off one layer means subtracting 10 squares from the above numbers like this:
60 - 10 = 50. 

Answer: we end up with 50 littles squares. 
denis23 [38]3 years ago
7 0

Answer:

<h2>512 cubes.</h2>

Step-by-step explanation:

We know that the volume of a cube is

V=s^{3}

Where V is volume and s is side.

If we have 10 little squares on each side, the volume is

V=10^{3}=1000u^{3}

If we peeled of the outer layer, that means 10-2=8, so the total number of cubes reaming is represented by the reduced volume

V=8^{3}u^{3}=512

Therefore, we would end up with 512 cubes.

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Can someone help me find the area and perimeter please?​
Lelu [443]

Answer:

Step-by-step explanation:

Remember that the formula to get the area of a right triangle is base times height divided by 2, so to find the area:

5 x 12 = 60/2 = 30

Area of this triangle is 30.

To find the perimeter, add all the sides:

5 + 12 + 13 = 30.

Perimeter of this triangle is 30.

7 0
2 years ago
X^2 + 8x + c<br> What is c ?
katrin [286]

Answer:

C is a constant ( a value that doesn't change)

Step-by-step explanation:

for example (X^2), here x is a variable with an exponent. (8x), here 8 is a coefficient. making c a constant.

8 0
3 years ago
if all of the medians of a triangle were constructed, what would the point where they all intersect be called?
Lubov Fominskaja [6]

Answer:

i think its centroid not sure though.

Step-by-step explanation:

3 0
3 years ago
In simplest radical form, what are the solutions to the quadratic equation 6 = x2 – 10x?
vichka [17]

Answer:

x = 5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}

Step-by-step explanation:

We need to solve the quadratic equation

6 = x^2 -10x

Rearranging we get,

x^2-10x-6=0

Using quadratic formula to solve the quadratic equation

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a= 1, b =-10 and c=6

Putting values in the quadratic formula

x=\frac{-(-10)\pm\sqrt{(-10)^2-4(1)(-6)}}{2(1)}\\x=\frac{10\pm\sqrt{100+24}}{2}\\x=\frac{10\pm\sqrt{124}}{2}\\x=\frac{10\pm\sqrt{2*2*31}}{2}\\x=\frac{10\pm\sqrt{2^2*31}}{2}\\x=\frac{10\pm2\sqrt{31}}{2}\\x = 5\pm\sqrt{31}

So, x=5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}

3 0
3 years ago
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Margaret [11]
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