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marusya05 [52]
3 years ago
11

Math. Please help. ASAP

Mathematics
1 answer:
S_A_V [24]3 years ago
6 0

Answer:


Step-by-step explanation:

ABC and DEF are congruent

ABC and JKL are not congruent

ABC and QRS are congruent

JKL and DEF are not congruent

JKL and QRS are not congruent

QRS and DEF are congruent

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Is this a 3-4th fraction
mezya [45]

Answer:

The clock hand made a 90 degree turn. It is not a 3/4 fraction.

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Emma has a board 5 feet long and cuts it into 6 equal pieces how long in feet is eacgpeace if the board in a fraction
il63 [147K]

Answer:

Imagine an easier version of this problem:  You have a board 5 feet long that you must cut (divide, right?) into two equal parts.  It is probably clear to you that you simply divide the length (5) by the number of parts you're dividing it into (2) to obtain the length of each piece (2.5 feet).

Use the same method for your problem 5 feet divided by 6 is 0.83 feet per piece.

We do not ordinarily divide feet into decimal portions, but instead into inches.  Since an inch is 1/12 of a foot, you could simply say 5/6 = how many twelfths?  or 5/6 = n/12  Solve this by inspection or by cross multiplying 5 times 12 equals n times 6.  So n must equal 10, and your pieces of board are each 10 inches long.

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3 years ago
A line is an undefined term because it
lina2011 [118]
It is undefined when the denominator is 0
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3 years ago
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How many eighths in one half
11111nata11111 [884]
4/8 = 1/2 so it is four eigths in one half.  4/8 simplified is 1/2
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3 years ago
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A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 201.9-cm and a standard dev
Nesterboy [21]

Answer:

There is a 0.08% probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 201.9-cm and a standard deviation of 2.1-cm. This means that \mu = 201.9, \sigma = 2.1.

For shipment, 9 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

By the Central Limit Theorem, since we are using the mean of the sample, we have to use the standard deviation of the sample in the Z formula. That is:

s = \frac{\sigma}{\sqrt{n}} = \frac{2.1}{\sqrt{9}} = 0.7

This probability is 1 subtracted by the pvalue of Z when X = 204.1.

Z = \frac{X - \mu}{\sigma}

Z = \frac{204.1 - 201.9}{0.7}

Z = 3.14

Z = 3.14 has a pvalue of 0.9992. This means that there is a 1-0.9992 = 0.0008 = 0.08% probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

3 0
3 years ago
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