Question

A pyramid has a horizontal square base of 12cm. the vertex of the pyramid is 7cm vertically above the base. calculate, correct to one decimal place:
(i) the length of the slant height

Answer 1

Answer:

9.2 cm.

Step-by-step explanation:

A pyramid has a horizontal square base of 12 cm. The vertex of the pyramid is 7 cm vertically above the base.

So, the height of the pyramid is 7 cm and half-length i.e. half base is equal to $\frac{12}{2} = 6$ cm.

Now, the slant height of a pyramid is the altitude of the side triangles.

Therefore, the length of the slant height will be equal to $\sqrt{6^{2} + 7^{2}} = 9.219$ cm ≈ 9.2 cm. (Answer)