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2 years ago

I need help with number 1 P.S DONT JUDGE ME AM ONLY A 9 YEAR OLD GIRL THAT IS IN 3RD GRADE

Mathematics

2 answers:

grigory [225]2 years ago

5 0

You would do 11 times 8 because you need all the legs of the spiders.
So, there would be 88 spider legs. 88 would be your answer.

LekaFEV [45]2 years ago

3 0

88 legs.
8 x 11 is 88.

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The large and medium shapes are scale drawings of the smallest shape the scale factor from the large shape to the media shape is

vovangra [49]

Answer:

Step-by-step explanation:

Add 65+40 which is going to give you 105 then once you get 105 subtract 65-40 which is going to give you 25 the 105 is the total so the whole answer is 25

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2 years ago

Which of the following are coefficient

malfutka [58]

Answer:

2 and -3

Step-by-step explanation:

because a coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 4 in 4x).

so in 2x-3y+5, 2 and -3 are the coefficients.

4 0

2 years ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

2 years ago

If y=x+1 on a straight line graph where does it meet

mojhsa [17]

I assume you're asking where it meets the y axis
In an equation the last number is the y intercept so I'm this case it would be 1

8 0

2 years ago

Mrs. White graded 85% of her class papers. If there are 60 papers in all, how

eimsori [14]

Answer:

MRS. White graded 51 papers.

Step-by-step explanation:

85/100= 0.85

0.85 x 60 = 51

3 0

2 years ago

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