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ohaa [14]
3 years ago
5

Roots, stems, leaves, and flowers all play integral roles in the life of a plant. Think about what you learned in this unit and

decide which of these parts is most important to plants and, therefore, to the survival of life on Earth. Defend your answer.
Biology
1 answer:
MrMuchimi3 years ago
5 0
I think the roots are the most important part of a plant because without the roots the stem and leaves would have no job
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Which of the following is a biotic factor that could reduce a population of frogs
Feliz [49]

C.

Biotic mean alive, so we can cut off the first 2 easily. Aquatic birds eat frogs, so that one is safe for now. A decrease in something parasitic usually helps the population, so D is out too. The only one left is C.

4 0
3 years ago
Challenge: baking powder is a combination of three substances. one is an acid salt, and the other two are
Mnenie [13.5K]

Answer:

baking soda and corn starch

Explanation:

im working on the same lab right now im almost done if you need any help

7 0
2 years ago
Sodium bicarbonate is an old standby antacid. it is not recommended for persons suffering from high blood pressure because
Dimas [21]
<span>The sodium in sodium bicarbonate increases the sodium concentration in the blood stream. Through osmosis, larger amounts of water enters the blood stream, thereby increasing the person's blood pressure. For persons with already high blood pressure, this can prove to be dangerous.</span>
6 0
3 years ago
Indicate the expected number of Barr bodies in interphase cells of individuals with Klinefelter syndrome; Turner syndrome; and k
madreJ [45]

Answer:

Barr bodies are small bodies that are dark staining bodies that show the inactivated X chromosome, these sex chromatin bodies attach to the membrane of the nucleus of interphase cells.

One less of the total number of X-chromosome (n-1) represents the number of Barr bodies.

Then,

The number of Barr bodies with Klinefelter would be:

Klinefelter (47,XXY): (n-1) = (2-1) = 1 Barr body as here two X chromosome present.

Similarly, for

Turner (45,XO): (n-1) = (1-1) = 0 Barr bodies (X chromosome = 1)

Now, as per the question, the bar bodies for karyotypes given

47,XYY: (n-1) = (1-1) = 0 Barr bodies

47,XXX: (n-1) = (3-1) = 2 Barr bodies

48,XXXX: (n-1) = (4-1) = 3 Barr bodies

7 0
3 years ago
Answers amoeba sisters: video recap meiosis
Schach [20]

1. Interphase is an important and the longest phase of the cell cycle during which the cell prepares for division by coping its DNA. It is metabolic phase of the cell, in which the cell grows, obtains nutrients and metabolizes them. There are three stages of interphase: G1 (the cell growth), S (replication of DNA, chromosomes are copied) and G2 (preparation for division). Without this phase, genetic material wouldn’t be ready for the process of meiosis  and haploid gametes couldn’t be created.

2. Homologous chromosomes are the similar but not totally identical chromosome pairs that an organism receives from its two parents. During the prophase I of meiosis they pair up: each chromosome aligns with its homologue partner via link-chiasmata ( the two match up at corresponding positions). Those homologue pairs separate during a first stage of cell division (meiosis I-reduction of chromosomes number, from diploid to haploid), while sister chromatids separate during a second stage (meiosis II).

3. Crossing over is a process in which homologous chromosomes trade their parts. Crossing over is process of genetic recombination where DNA is cut and then repaired. Cut and repair of homologous chromosomes allow them to exchange some of their genetic information. As a consequence of crossing over, new arrangement of maternal and paternal alleles on the same chromosome is achieved. It is the way to create varations.

4. During the metaphase I, homologue pairs are lined up comparing to metaphase II where individual chromosomes are lined up. It is because during the meiosis I homologue pairs separate and chromosome number reduce from diploid to haploid. On the other hand, during the meiosis II, sister chromatids separate.

5. Nondisjunction is the consequence of cell division, where there is no properly separation. There are  different forms of nondisjunction:  

• failure of a pair of homologous chromosomes to separate in meiosis I,  

• failure of sister chromatids to separate during meiosis II.

After nondisjunction, resulting daughter cells are with abnormal chromosome numbers -aneuploidy.


4 0
3 years ago
Read 2 more answers
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