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Studentka2010 [4]
3 years ago
14

What is the value of f(x) = 3x - 5 when x = 6

Mathematics
1 answer:
egoroff_w [7]3 years ago
4 0

Plug in 6 for x in the equation:

f(6) = 3(6) - 5

Remember to follow PEMDAS. First, multiply

f(6) = 3(6) - 5

f(6) = 18 - 5

Finally, subtract

f(6) = 18 - 5

f(6) = 13

f(6) = 13 is your answer

hope this helps

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alexandr1967 [171]

Answer:

1) 48p^2+4p-4

2)40b^2-45b+5

3)3p^2-6p+3

4)3v^2-6v+3

5)40x^2+28x+24

6)3x^2+15x+12

Step-by-step explanation:

6 0
3 years ago
Please need with one
dezoksy [38]
48+27=75

27/75 x 100 = 36% regular soda

8 0
3 years ago
Now, write x² - 16x + 64 = -8 as
topjm [15]

Answer:

(x-8)^2=-8

Step-by-step explanation:

Just did it

7 0
3 years ago
What is the messure of N and the two angles; an-16 and 6n
AURORKA [14]

Answer:

14, 96,84

Step-by-step explanation:

8n  - 16 + 6n = 180 {Supplementary angles}

<u>8n + 6n</u>  -16 = 180

Combine like terms

14n - 16 = 180

Add 16 to both sides

14n = 180 + 16

14n = 196

Divide both sides by 14

n = 196/14

n = 14

8n - 16 = 8*14 - 16 = 112 - 16 = 96

6n = 6 *14 = 84

7 0
2 years ago
A county is considering rasing the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 m
DochEvi [55]

Answer:

No, at alpha equals 0.10​, we do not have enough evidence to support the​ county's claim.

Step-by-step explanation:

We are given that a county is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 miles per hour.

A random sample of 15 vehicles has a mean speed of 31 miles per hour and a standard deviation of 4.7 miles per hour.

<em><u>Let </u></em>\mu<em><u> = true mean speed of the vehicles.</u></em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \leq  30 miles per hour   {means that the mean speed of vehicles is lesser than or equal to 30 miles per hour}

<u>Alternate Hypothesis,</u> H_A : \mu > 30 miles per hour   {means that the mean speed of vehicles is greater than 30 miles per hour}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean speed of 15 vehicles = 31 mph

             s = sample standard deviation = 4.7 mph

             n = sample of vehicles = 15

So, <em><u>test statistics</u></em>  =   \frac{31-30}{\frac{4.7}{\sqrt{15} } }  ~ t_1_4

                               =  0.824

<u><em>Hence, the value of test statistics is 0.824.</em></u>

<em />

<em>Now at 0.10 significance level, the t table gives critical value of 1.345 at 14 degree of freedom for right-tailed test. Since our test statistics is less than the critical value of t as 0.824 < 1.345, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>

<em />

Therefore, we conclude that the mean speed of vehicles is lesser than or equal to 30 miles per hour which means that the county's claim is not supported.

4 0
3 years ago
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