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sergiy2304 [10]
3 years ago
9

(5-^2)-^4 PLEASE TELL ME EHSY THIS IS

Mathematics
1 answer:
Ad libitum [116K]3 years ago
5 0

390625

^if that’s what you meant in the picture cause your question was confusing

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Figure ABCD is a parallelogram with point C (3, -2). What rule would rotate the figure 90 degrees clockwise, and what coordinate
WITCHER [35]
      Coordinates of C ( 3, - 2 ). After the rotation for 90° clockwise new coordinates would be C ` ( - 2, - 3 ).
      Answer:
      B ) ( x , y ) → ( y, -x ) ;   C`( -2, - 3 )  
4 0
3 years ago
Read 2 more answers
I REALLY NEED HELP PLEASE
Nezavi [6.7K]

Answer:

10

Step-by-step explanation:

given

\frac{s + ( - 7)}{ - 1}

we first need to simplify the expression before we find it's value when s=-3

positive times negative=negative

so the equation becomes

\frac{s - 7}{ - 1}

substituting s=-3 into the equation.

\frac{ - 3 - 7}{ - 1}

=

\frac{ - 10}{ - 1}

=the negatives cancel out leaving

= 10

7 0
3 years ago
How do you write 2.6 × 10 to the 3 power in standard form?
Novay_Z [31]

Answer:

no u

Step-by-step explanation:

7 0
3 years ago
If
Anna11 [10]
Answer: -104

Explanation: x=-9 y=2
2(y-3xy)
=2(2-3(-9)(2))
=4-2(3(-18))
=4-108
=-104

Hope it helped

4 0
2 years ago
What is the function that defines the following sequence? 10, 12, 14, 16, 18…
Furkat [3]

The sequence shown is defined by a function that generates <em>even</em> numbers equal or greater than 10, defined by the function s = 10 + 2 · (n - 1).

<h3>How to define the function behind a sequence</h3>

Sequences are sets of elements characterized by at least a rule. In this case, the sequence shown is characterized by a function that generates even numbers equal or greater than 10. The function behind the sequence is shown below:

s = 10 + 2 · (n - 1)     (1)

Where n is the <em>element</em> index.

The sequence shown is defined by a function that generates <em>even</em> numbers equal or greater than 10, defined by the function s = 10 + 2 · (n - 1).

To learn more on sequences: brainly.com/question/21961097

#SPJ1

4 0
1 year ago
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