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Dvinal [7]
3 years ago
15

A. 117.2 B. 468.9 C. 410.3 D. 205.1

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer:

The answer is C

Step-by-step explanation:

Fuente: Mis huevos

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Can someone please help me?
Crazy boy [7]

Answer:

70°

Step-by-step explanation:

since two lengths are equal to 3.5 that’s means there’s are two equal angles (55° and 55°)

a triangle adds up to 180°

so to find x we set this up:

x +55 +55 = 180

x + 110 = 180

x = 70°

3 0
2 years ago
A coat that usually costs $120.00 is marked 1/3 off. What is the sale price of the coat?
dedylja [7]

If the coat is 120$ then 1/3 is taken off it would be 80$

Step-by-step explanation:

1/3 of 120 is 40. 40x 3 is 120.

7 0
3 years ago
Read 2 more answers
HELP ASAP WITH THIS QUESTION
alexgriva [62]
Hey there (again)

x = 2y  \\ y = -2  \\ x = 2(-2) \\x= -4 \\ \\ \\ w + xy + 4x^2  = 2\\ w+-4(-2) + 3(-4)^2 = 2 \\ w + 8 + 3(16) = 2 \\ w + 8 + 48 = 2 \\ Subtract56: w + 56 =2 \\ 56 - 56 (Cancel) \\ 2 - 56 = -54 \\ w = -54

Answer: B  the simplification performed in step 2 is invalid or incorrect

Good luck on your assignment and enjoy your day 

~MeIsKaitlyn:)
5 0
3 years ago
I trying to simplify ( 14+5) +15÷2 PLEASE HELP this is a 5th grade math question
sertanlavr [38]

Answer:

14+5 = 19

19 + 15/2

15/2 = 7.5

19+7.5 = 26.5


Just remember PEMDAS!

Pls mark brainliest

Step-by-step explanation:


6 0
3 years ago
The sum of four times a number and five times another number is -28. The sum of nine times the first number and two times the se
Rina8888 [55]

Answer:

<h2>3 and -8</h2>

Step-by-step explanation:

x,\ y-the\ numbers\\\\\text{The sum of four times a number and five times another number is -28:}\\\\4x+5y=-28\\\\\text{The sum of nine times the first number and two times the second number is 11:}\\\\9x+2y=11\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}4x+5y=-28&\text{multiply both sides by2}\\9x+2y=11&\text{multiply both sides by (-5)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}8x+10y=-56\\-45x-10y=-55\end{array}\right}\qquad\text{add both sides of the equation}

.\qquad-37x=-111\qquad\text{divide both sides by (-37)}\\.\qquad\qquad\boxed{x=3}\\\\\text{Put the value of x to the first equation:}\\\\4(3)+5y=-28\\12+5y=-28\qquad\text{subtrac 12 from both sides}\\5y=-40\qquad\text{divide both sides by 5}\\\boxed{y=-8}

3 0
2 years ago
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