Answer:
5.23 LAB: Adjust values in a list by normalizing When analyzing data sets, such as data for human heights or for human weights, a common step is to adjust the data. This can be done by normalizing to values between 0 and 1, or throwing away outliers.
Explanation:
Improving SEO, by ensuring the URL matches the title of your
blog post, word for word is False.
<h3>What is SEO?</h3>
This is referred to as Search engine optimization. It is used to
improve a site by ensuring that is more visible when people
search for certain things or words.
The URL should contain only key words and unnecessary ones
should be eliminated which is why it isn't compulsory for the title
to be word for word.
Read more about Search engine optimization here brainly.com/question/504518
1.)
<span>((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) </span>
<span>The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. </span>
<span>For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. </span>
<span>a.) (i <= n) || (i >= n) </span>
<span>This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. </span>
<span>b.) (a[i] == 0) && (a[i-1] == 0) </span>
<span>This means that both of these terms are true. We substitute. </span>
<span>((i <= n) && true) || (((i >= n) && true)) </span>
<span>Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: </span>
<span>(i <= n) || (i >= n) </span>
<span>This is clearly always true. </span>
A) <span>unauthorized duplication of software </span>
