If the framed picture is shaped like a square and has a 12 square foot surface area, then the answer is yes, it will fit flush against the edge of the crate.
Given Part A:
the volume of the cube = 64 cubic feet
therefore, ∛64 = 4 feet
hence one edge measures 4 feet.
Now for Part B:
the area of the square is 12 square feet.
hence, √12 = 3.36 feet.
we can observe that 3.46<4
which indicates that the area covered by the painting is less than that of the one side of the crate, which makes it easy for the painting to fit in the crate.
Hence the painting will fit a side of crate.
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While packing for their cross-country move, the Chen family uses a that has the shape of a cube. PART A PART B If the crate has the volume V = 64 cubic feet, The Chens want to pack a large, framed painting. If an area of 12 square feet , will the painting fit flat what is the length of one edge? the framed painting has the shape of a square with against a side of the crate? Explain.
Step-by-step explanation:
(X1,Y1) = (-2,2)
(X2,Y2) = (0,1)
• Find slope.
m = (Y2 - Y1)/(X2 - X1)
m = (1 - 2)/(0 - (-2))
m = -1/2
The answer is C.
Answer:
z = 17.5
Step-by-step explanation:
segment RX is an angle bisector and divides the opposite side into segments that are proportional to the other 2 sides, that is
= 
, substitute values
= 
( cross- multiply )
6z = 105 ( divide both sides by 6 )
z = 17.5
Infinitely many solutions
Answer:
X + Y + Z = 32
X2 = Y
X3 + 2 = Z
X + X2 + X3 + 2 = 32
Make X alone
There is a 2 so we subtract 2 from both sides
X + X2 + X3 = 30
Add the X's up
X + X2 + X3 = X6
X6 = 30
Divide by 6
30 / 6 = 5
You are left with X=5
The first piece of wood has a length of 5
5 x 2 = 10
The second piece has a value of 10
5 x 3 + 2 = 17
The third piece is 17
Hope this helps. If you have any questions you may ask.
Step-by-step explanation:
