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faltersainse [42]
3 years ago
15

Help, what are the angles?

Mathematics
2 answers:
Sav [38]3 years ago
7 0
I’m not sure about the first but I know the second one is right angles
Tasya [4]3 years ago
5 0

Answer:

The angle names are ‘angle c’, ‘angle acb’ and ‘angle bca’. The angle names will always be the three coordinates in series, or the letter of the vertex sof the angle.

it looks to be acute, or less than 90 degrees in measure, but it is hard to tell because it could also be right. If it has a square In the corner it is right, and if it looks to be larger than 90 degrees it is obtuse.

the interior is in the corner that the angle creates, and the exterior is outside of that angle.

Step-by-step explanation:

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yequals(9 x Superscript 4 Baseline minus 4 x squared plus 6 )Superscript 4 To find StartFraction dy Over dx EndFraction ​, write
damaskus [11]

Answer:

Step-by-step explanation:

Given the function

y = (9x⁴ — 4x² + 6)⁴

We need to find the derivative of y with respect to x i.e. dy/dx.

So let u = 9x⁴—4x² + 6

Then y = u²,

Then, y is a function of u, y=f(u)

Also, u is a function of x, u = g(x)

In this case,

u = g(x) = 9x⁴—4x² + 6

So let differentiate this function y(x).

This is a function of a function

Then, we need to find u'(x)

u (x) = 9x⁴—4x² + 6

Then, u'(x) = 36x³ — 8x

Also we need to find y'(u)

Then, y = u²

y'(u) = 2u

Using function of a function formula

dy / dx = dy/du × du/dx

y'(x) = y'(u) × u'(x)

y'(x) = 2u × 36x³ — 8x

y'(x) = 2u(36x³ — 8x)

Since, u = 9x⁴—4x² + 6

Therefore,

y'(t) = 2(9x⁴—4x² + 6)(36x³ — 8x)

So,

dy/dx = 2(9x⁴—4x² + 6)(36x³ — 8x)

dy/dx = (18x⁴—8x² + 12)(36x³ — 8x)

5 0
3 years ago
Simplify the following expression.<br> ?<br> 9t2 + 7t + 4 - 2t2 + 5t
Katen [24]

Answer:

I'm assuming the 2 after 9t and -2t means squared.

7t² + 12t + 4

Step-by-step explanation:

To simplify the expression we should combine like terms. Like terms are terms with same variables and powers.

Let's start with 9t² and -2t² since they have the same variable and power of t². To combine them we should add them together which would be: 9t² + (-2t²) = 9t² - 2t² = 7t²

Next we can combine 7t and 5t since they have the same variable and power of t. 7t + 5t = 12t

4 doesn't have any like terms so we leave it as it is.

Lastly we add all of our terms: 7t² + 12t + 4

6 0
2 years ago
Please help me with this. I thought the answer was 9 but I was wrong.
Lilit [14]

I think your answer is 28

3 0
3 years ago
Read 2 more answers
The first term of a geometric sequence is −2 and the common ratio is 3. What is the fourth term of the sequence?
Nat2105 [25]

Answer: -54

Step-by-step explanation:

The question is the first term of a geometric sequence is −2 and the common ratio is 3. The formula for finding the nth term of a geometric sequence is: ar^n-1

where,

a = first term = -2

r = common ratio = 3

n = number of terms = 4

The solution has been attached. The answer is -54

5 0
3 years ago
Question 16 of 50
saul85 [17]
Equation:

y=6,000(1.05)^5

Answer:
7657
8 0
1 year ago
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