Question

uppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read the base titrant volume as 2.03 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 20.03 mL. What volume of base was required for the titration

Answer 1

Answer:

$V_{base}=18.00mL$

Explanation:

Hello,

In this case, since you have both the final and initial volume for the titration procedure, clearly, the used volume is computed by the subtraction between them, since it accounts for the employed volume of the base, it turns out:

$V_{base}=20.03mL-2.03mL\\\\V_{base}=18.00mL$

Best regards.