Thickness of cooper sheet is 0.048 cm (Approx.)
Given that;
Density of copper = 8.96 g/cm³
Measures of copper sheet = 5.5 cm × 5.5 cm
Mass of of copper sheet = 12.96 gram
Find:
Thickness of cooper sheet
Computation:
Volume = Mass / Density
Volume of cooper = 12.96 / 8.96
Volume of cooper = 1.4464
Volume of cooper = 1.45 cm³ (Approx.)
Volume of cooper sheet = 5.5 cm × 5.5 cm x Thickness
5.5 cm × 5.5 cm x Thickness = 1.45
Thickness of cooper sheet = 0.04793
Thickness of cooper sheet = 0.048 cm (Approx.)
Learn more:
brainly.com/question/24235924?referrer=searchResults
Answer:
Option B. A
Explanation:
From the question given above, the following data were obtained:
C(s) + 2H₂ (g) —> CH₄ (g). ΔH = –74.9 kJ
From the reaction above, we can see that the enthalpy change (ΔH) is negative (i.e –74.9 KJ) which implies that the heat content of the reactants is greater than the heat content of the products. Thus, the reaction is exothermic reaction.
For an exothermic reaction, the energy profile diagram is drawn in such a way that the heat content of reactants is higher than the heat content of products because the enthalpy change
(ΔH) is always negative.
Thus, diagram A (i.e option B) gives the correct answer to the question.
A. Carbon monoxide
b. Phosphorous trichloride
c.
d.nitrogen
e. Water- Hydrogen - Oxygen
f.
Answer:
The answer to this can be arrived at by clculating the mole fraction of atoms higher than the activation energy of 10.0 kJ by pluging in the values given into the Arrhenius equation. The answer to this is 20.22 moles of Argon have energy equal to or greater than 10.0 kJ
Explanation:
From Arrhenius equation showing the temperature dependence of reaction rates.
where
k = rate constant
A = Frequency or pre-exponential factor
Ea = energy of activation
R = The universal gas constant
T = Kelvin absolute temperature
we have
Where
f = fraction of collision with energy higher than the activation energy
Ea = activation energy = 10.0kJ = 10000J
R = universal gas constant = 8.31 J/mol.K
T = Absolute temperature in Kelvin = 400K
In the Arrhenius equation k = Ae^(-Ea/RT), the factor A is the frequency factor and the component e^(-Ea/RT) is the portion of possible collisions with high enough energy for a reaction to occur at the a specified temperature
Plugging in the values into the equation relating f to activation energy we get
or f = 
= 20.22 moles of argon have an energy of 10.0 kJ or greater
