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Likurg_2 [28]
3 years ago
9

After its first day of life, a baby blue whale started growing. It grew 47.075 inches. If the average baby blue whale grows at a

rate of 1.5 inches a day, for how many days did the baby whale grow, to the nearest tenth of a day?
Mathematics
2 answers:
pantera1 [17]3 years ago
7 0

I believe its 31 days

I divided and got the answer

skad [1K]3 years ago
4 0

Answer:

After the first day, Length of baby blue whale=47.075 inches

It is given that, average baby blue whale grows at a rate of 1.5 inches a day.

⇒ To the nearest tenth of a day, increase in Height of baby blue whale will be

=47.075 \times \frac{1.5}{10}\\\\=7.06125  inches        

Number of Days for which the baby whale grow, to the nearest tenth of a day

    =\frac{47.075}{7.06125}\\\\=6.67

=Approximately 7 days

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Answer: In your problem, you said that they are squared. However, it is not written as squared. We just have to multiply them.

We can use the FOIL method.

(3b - 5c)(3x + 5y)

6bx + 15by - 10cx - 25cy

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8 0
3 years ago
Use the following data set to answer numbers 1 - 4.
alukav5142 [94]

Answer:

1. 13+18+13+14+13+16+14+21+13

= 145/9

=16.11

2. Range =145

3. Mode =13

4. Median =14

Step-by-step explanation:

6 0
2 years ago
Can someone please help me with this maybe get a better understanding if you have the time to tell me?
Colt1911 [192]

Step-by-step explanation:

Absolute value function:

  • |x| = x when x >= 0.
  • |x| = -x when x < 0.

Swim 3 feet under water => |-3|

Stand 20 feet above => |20|

Using the absolute value function,

we have |-3| = 3 and |20| = 20.

Since 3 is less than 20, |-3| < |20|. (C)

5 0
2 years ago
I NEED HELP !!! 30 points!!!! and brainliest :)<br><br>please give sensible answer :(<br><br><br>​
Allushta [10]

Answer:

Step-by-step explanation:

9) PQR Is an isosceles triangle

=> ∠PRQ = (180° - x)/2

PRS is an isosceles right triangle

=> ∠PRS = 45°

Have: ∠PRS + ∠PRQ = 115°

=> \frac{180-x}{2}+45=115 \\

=> 180 - x = (115 - 45).2 = 140

<=> x = 180 - 140 = 40

10) ABD is an isosceles right triangle => ∠ABD = 45°

BCD is an equilateral triangle => ∠CBD = 60°

have: x = ∠ABD + ∠CBD = 45° + 60° = 105°

11) have: x = y (2)

PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40

QTS   is an isosceles triangle => ∠TQS = 180 -2x

QRS   is an isosceles triangle => ∠RSQ = y

have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)

(1)(2) => \left \{ {{y=x} \atop {2x-y=40}} \right.\\\\=> \left \{ {{x=40} \atop {y=40}} \right.

=> x + y = 80

12) EFJ Is an equilateral  triangle => ∠FJE = 60

∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle

=> 60 = 2.∠JHF => ∠JHF = 30°

∠JHF is the outer angle of the triangle FHG

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7 0
2 years ago
The radius of a circle is 15. Using π, which equation expresses the ratio of the circumference to the diameter of a circle?
Kobotan [32]

Answer:

The equation which expresses the ratio of the circumference to the diameter of a circle is  \frac{C}{30}=\pi ⇒ D

Step-by-step explanation:

π is the ratio between the circumference of the circle and the length of its diameter

\frac{C}{d}=\pi , where

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  • d is the diameter of the circle

∵ The circumference of the circle is C

∵ The radius of the circle is 15 units

∴ r = 15 units

- Find the diameter of the circle

∵ The diameter of the circle d = 2 r

∴ d = 2(15) = 30 units

∴ The diameter of the circle is 30 units

∵ \frac{C}{d}=\pi

∵ d = 30 units

∴ \frac{C}{30}=\pi

The equation which expresses the ratio of the circumference to the diameter of a circle is  \frac{C}{30}=\pi

6 0
3 years ago
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