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Likurg_2 [28]
2 years ago
9

After its first day of life, a baby blue whale started growing. It grew 47.075 inches. If the average baby blue whale grows at a

rate of 1.5 inches a day, for how many days did the baby whale grow, to the nearest tenth of a day?
Mathematics
2 answers:
pantera1 [17]2 years ago
7 0

I believe its 31 days

I divided and got the answer

skad [1K]2 years ago
4 0

Answer:

After the first day, Length of baby blue whale=47.075 inches

It is given that, average baby blue whale grows at a rate of 1.5 inches a day.

⇒ To the nearest tenth of a day, increase in Height of baby blue whale will be

=47.075 \times \frac{1.5}{10}\\\\=7.06125  inches        

Number of Days for which the baby whale grow, to the nearest tenth of a day

    =\frac{47.075}{7.06125}\\\\=6.67

=Approximately 7 days

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For a moving object, the force acting on the object varies directly with the objects acceleration. When a force of 35 N acts on
Genrish500 [490]
<h3>Answer:  3 m/s^2</h3>

=======================================================

According to Newton's Second Law, we know that

F = m*a

where F is the force applied, m is the mass and 'a' is the acceleration.

We see that this is a direct variation equation for F and a, such that m is the constant of variation. It's similar to how y = kx is also a direct variation equation.

Plug in F = 35 and a = 5 to find m

F = ma

35 = m*5

35/5 = m

7 = m

m = 7

The object has a mass of 7 kg

Our equation F = ma updates to F = 7a

Now plug in the force F = 21 to find 'a'

F = 7a

21 = 7a

21/7 = a

3 = a

a = 3

The acceleration will be 3 m/s^2

Notice how a smaller force applied means that the acceleration has also gone down as well.

8 0
2 years ago
Select True or False for each statement.
Margarita [4]
The first statement and the second statement are FALSE.

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I hope my answer has come to your help. God bless you and have a nice day ahead!
7 0
3 years ago
Find x.<br><br><br><br> \/3<br> 1.5<br> 3 \/3<br> 2
serg [7]

x = \sqrt{3}

Step-by-step explanation:

Given:

\sin(ABC) =  \frac{AC}{AB}

=  >  \sin(60) =  \frac{3}{AB}

=  >AB= 2 \sqrt{3}

Now by Pythagoras theorem,

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Substituting values,

{3}^{2} +  {x}^{2} = (2 \sqrt{3})^{2}

=  >  {x} =  \sqrt{3}

Hence, value of x is \sqrt{3}

3 0
2 years ago
Read 2 more answers
Help anyone can help me do this question,I will mark brainlest.​
Luda [366]

Answer:

344 {cm}^{2}

Step-by-step explanation:

area \: of \: the \: square \\  = 40cm \times 40cm \\  = 1600 {cm}^{3}  \\

area \: of \: the \: circle \\  = \pi {r}^{2}  \\  = 3.14 \times  {(20)}^{2}  \\  = 3.14 \times 400 \\  = 1256 {cm}^{2}  \\

area \: of \: shaded \: region \\  = 1600 {cm}^{2}  - 1256 {cm}^{2}  \\  = 344 {cm}^{2}  \\

3 0
3 years ago
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