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3 years ago

10

a number is less than 200 and greater than 100 the ones digit is 5 less than 10.the tens digit is 2 more than the ones digit.wha

t is the number

1 answer:

postnew [5]3 years ago

5 0

It's between 101 and 199.

5 less than 10 is 5.
2 more than 5 is 7

My guess is 157

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Three houses for of a bag of flour to make how many bags of flour does grandma need to buy if she is making 10 dozen cookies

SCORPION-xisa [38]

Assuming you meant 3 dozen for a bag of flour the answers 4
If you meant 3 cookies for a bag of flour the answers 10

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3 years ago

What is the answer to this:<br> (2^2)^2/2*2^4

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Answer:

64

Step-by-step explanation:

2^2*2^4

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3 years ago

Read 2 more answers

kenny6666 [7]

Answer and Explanation:

To find : Which number is in standard notation or scientific notation?

Solution :

Scientific notation is a special ways of writing the standard form of number.

Scientific notation make a big number into smaller way bye writing it into 10 to the power or using E.

Standard notation is like 12,47950585,89000.

Scientific notation is like $1.43\times 10^3$ , $1.43E10$

So, Now we examine the numbers,

A) $5.9E10$ is the Scientific notation.

B) $0.0000734$ is the Standard notation.

C) $2.66\times 10^{-3}$ is the Scientific notation.

D) $641,000,000,000$ is the Standard notation.

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3 years ago

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In an effort to determine whether any correlation exists between the price of stocks of airlines, an analyst sampled six days of

vovikov84 [41]

Answer:

Check the explanation

Step-by-step explanation:

Following table shows the calculations:

Delta, X Southwest , Y X^2 Y^2 XY

45.96 38.76 2112.3216 1502.3376 1781.4096

46.8 45.41 2190.24 2062.0681 2125.188

47.93 15.7 2297.2849 246.49 752.501

51.78 49.58 2681.1684 2458.1764 2567.2524

52.17 44.34 2721.7089 1966.0356 2313.2178

47.36 18 2242.9696 324 852.48

Total 292 211.79 14245.6934 8559.1077 10392.0488

Sample size: n =6

Now

$S_{yy}=\sum y^{2}-\frac{\left (\sum y \right )^{2}}{n}=1083.27$

$S_{xx}=\sum x^{2}-\frac{\left (\sum x \right )^{2}}{n}=35.03$

$S_{xy}=\sum xy-\frac{\left (\sum x \right )\left (\sum y \right )}{n}=84.94$

The coefficient of correlation is :

$r=\frac{S_{xy}}{\sqrt{S_{xx}S_{yy}}}=0.436$

7 0

3 years ago

A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is

scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=360000$ represent the mean for the downtown restaurant

$\bar X_{2}=340000$ represent the mean for the freeway restaurant

$s_{1}=50000$ represent the sample standard deviation for downtown

$s_{2}=40000$ represent the sample standard deviation for the freeway

$n_{1}=36$ sample size for the downtown restaurant

$n_{2}=36$ sample size for the freeway restaurant

t would represent the statistic (variable of interest)

$\alpha=0.05$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis: $\mu_{1}\leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level $\alpha=0.05$ and $\alpha/2=0.025$ we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is $t_{1-\alpha/2}=1.66$

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874$

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

$p_v =P(t_{70}>1.874)=0.033$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0

3 years ago