Please help :C I have to get this question done asap or I'll get into trouble

Mathematics

1 answer:

AlekseyPX2 years ago

4 0

Ok, so it seems to be the square root of the cube root of 2

we just convert to exponential
remember
$(x^m)^n=x^{mn}$ and
$\sqrt[n]{x^m} =x^ \frac{m}{n}$

therfor

$\sqrt{ \sqrt[3]{2} }= \sqrt{2^ \frac{1}{3} } =( 2^ \frac{1}{3})^ \frac{1}{2} =2^ \frac{1}{6}$

last choice is correct

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I just need an explanation on why I was wrong and why the correct answer is correct

Alja [10]

Answer:

B 1

Step-by-step explanation:

Since the divisor is in the form of x - c, use what is called Synthetic Division. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

2| -2 1 5 0 4 1

↓ -4 -6 -2 -4 0

_________________

-2 -3 -1 -2 0 1→ -2x⁴ - 3x³ - x² -2x + [x - 2]⁻¹

You start by placing the c in the top left corner, then list all the coefficients of your dividend [-2x⁵ + x⁴ + 5x³ + 4x + 1]. You bring down the original term closest to c then begin your multiplication. Now depending on what symbol your result is, tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that -2 in your quotient can be a -2x⁴, and the -3 [x³] follows right behind it, then 1 [-x²], -2[x], and finally, [1\x - 2] (remainder is 1, so set it over your denominator, which is the divisor), giving you the other factor of -2x⁴ - 3x³ - x² -2x + [x - 2]⁻¹.

I am joyous to assist you anytime.

** $(x - 2)^{-1} = \frac{1}{x - 2}$