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Neporo4naja [7]
2 years ago
9

Find value of x of question number F ​

Mathematics
1 answer:
a_sh-v [17]2 years ago
6 0

Answer:

X=17

Step-by-step explanation:

AC^2=AB^2 +BC^2(PYTHAGOREAN THEORM)

100=64 +BC^2

36=BC^2

6CM=BC

AD^2=AB^2+BD^2(PYTHAGOREAN THEORM)

X^2 =64+225

X^2=289

X=17

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CEREAL of the 35 types of cereal sold in a store, 15are advertised to be whole grain. What fraction, in simplest form, of the ce
Vesnalui [34]

Answer:

The answer is 3/7

Step-by-step explanation:

Find the GCD of both 35 and 15.  This is 5.

Then, divide the numerator and denominator by the GCD.

15 ÷ 5/ 35 ÷ 5

This equals 3/7.

6 0
3 years ago
A room is 12 m long and 8 m wide and 10 m high, find the area of the room​.
Vikki [24]

Answer:

96 square meters

6 0
3 years ago
kaye has $2.80 in nickels and dimes. she has three timesas many dimes as nickels. how many nickels and how many dimes does she h
Vitek1552 [10]
8 nickels, because 8 (nickels) × 5 (worth) = 40
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4 0
3 years ago
Find the area of the triangle.
BabaBlast [244]

Answer:

17.7 cm^2

Step-by-step explanation:

Use trig to find the height of the triangle. Then the area is bh/2.

Extend side BC to the right until it is vertically below point A. Draw a segment from point A vertically down until it intersects the extension of side BC. Call the point of intersection D. <D is a right angle.

Use triangle ABD to find the height, AD, of triangle ABC.

For <B of 37 deg, AD is the opposite leg. AB is the hypotenuse. The trig ratio that relates the opposite lefg to the hypotenuse is the sine.

sin B = opp/hyp

sin 37 deg = AD/13.1

AD = 13.1 * sin 37 deg

AD = 7.9

AD is the height of triangle ABC. BC is the base. We can find the area of triangle ABC.

area = bh/2

area = (4.5 cm)(7.9 cm)/2

area = 17.7 cm^2

5 0
3 years ago
What is the probability of getting either a sum of 5 or at least one 5 in the roll of a pair of dice?
maria [59]
In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.

To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9

To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum).  The probability is 11/36

Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.

P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
4 0
3 years ago
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