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vladimir1956 [14]

4 years ago

9

When a pendulum is at maximum displacement, which statement is true? A. The potential energy is at its greatest point. B. The po

tential energy is at its lowest point. C. The amplitude is at its lowest point. D. The frequency is at its greatest point.

1 answer:

Afina-wow [57]4 years ago

3 0

Hello, Jcparris

Your answer is A. The potential energy is at its greatest point

If my answer helped you please leave a thank and rate it 5 stars and the most important please mark me as brainliest thank you and have the best day ever!

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(eText prob. 4.25 with some values changed) Air enters a diffuser of a jet engine operating at steady state at 2.65 psia, 389◦R,

krek1111 [17]

Answer:

$V_2 = 45.44m/s$

Explanation:

We have to many data in different system, so we need transform everything to SI, that is

$P_1 = 2.65 Psi = 18.271 kPa\\T_1= 389\°R = 216 K\\V_1 = 869ft/s = 264m/s\\T_2 = 450\°R = 250K$

When we have all this values in SI apply a Energy Balance Equation,

$\dot{Q}_{cv}-\dot{W}_{cv}+\dot{m}[(h_1-h_2)+(\frac{V_1^2-V_2^2}{2})+g(z_1-z_2)]=0$

Solving for V_2

$V_2 = \sqrt{V_1^2+2(h_1-h_2)}$

From the table of gas properties we calculate for $T_1 = 216K$ and $T_2 = 250K$

$h_1 = 209.97+(219.97-209.97)(\frac{216-210}{220-210})$

$h_1 = 215.97kJ/kg$

For T_2;

$h_2 = 250.05kJ/kg$

Substituting in equation for V_2

$V_2 = \sqrt{V_1^2+2(h_1-h_2)}$

$V_2 = \sqrt{265^2+2(215.97-250.05)*10^3}\\V_2 = 45.44m/s$

4 0

3 years ago

Which model could represent a neutral atom of nitrogen? 2 3 4 A. 1 B. 3 C. 4 D. 2.

Mrac [35]

Answer:

B

Explanation:

because it has more power

7 0

3 years ago

Read 2 more answers

What is the strength of the electric field 0.1 mmmm below the center of the bottom surface of the plate

Aleksandr [31]

Complete Question

A thin, horizontal, 12-cm-diameter copper plate is charged to 4.4 nC . Assume that the electrons are uniformly distributed on the surface. What is the strength of the electric field 0.1 mm above the center of the top surface of the plate?

Answer:

The values is $E =248.2 \ N/C$

Explanation:

From the question we are told that

The diameter is $d = 12 \ cm = 0.12 \ m$

The charge is $Q = 4.4 nC = 4.4 *10^{-9} \ C$

The distance from the center is $k = 0.1 \ mm = 1*10^{-4} \ m$

Generally the radius is mathematically represented as

$r = \frac{d}{2}$

=> $r = \frac{0.12}{2}$

=> $r = 0.06 \ m$

Generally electric field is mathematically represented as

$E = \frac{Q}{ 2\epsilon_o } [1 - \frac{k}{\sqrt{r^2 + k^2 } } ]$

substituting values

$E = \frac{4.4 *10^{-9}}{ 2* (8.85*10^{-12}) } [1 - \frac{(1.00 *10^{-4})}{\sqrt{(0.06)^2 + (1.0*10^{-4})^2 } } ]$

$E =248.2 \ N/C$

4 0

4 years ago

Josh starts throwing his pitch; we assume that his arm moves in a perfect circular arc, and his arm is 0.7 m long. If he needs t

harina [27]

As we know that centripetal acceleration is given as

$a_c = \frac{v^2}{R}$

here we know that

linear speed = 35 m/s

here radius of path is same as length of arm

R = 0.7 m

now from above above formula we have

$a_c = \frac{35^2}{0.7}$

$a_c = 1750 m/s^2$

so acceleration is 1750 m/s/s

5 0

4 years ago

If there is 10% sales tax on a car costing $18,000

MaRussiya [10]

Answer:

180

Explanation:

i think

6 0

3 years ago

Read 2 more answers