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kaheart [24]
3 years ago
15

when an object moves with constant velocity, does its average velocity during any time interval differ from its instataneous vel

ocity at any instant?
Physics
1 answer:
BigorU [14]3 years ago
8 0
For a constant-velocity object, the average and instantaneous are the same.  So the answer is no.  It's like taking a running average of a string of numbers that are all the same number.  The average is always the sum of the numbers divided by how many have accumulated, which will always equate to the repeated number.
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What location on earth experiences the most change the number of daylight hours?
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3 0
3 years ago
A pressure of 70N/m2 equals
laiz [17]

Answer:

Newton/square meters=70 AND Pascal=70

Explanation:

Formula:multiply the pressure value by 1.

6 0
2 years ago
Problem: Suppose that the rate of flow of water through a fire hose is 21.4 kg/s and the stream of water from the hose moves at
Sloan [31]

Answer:

The force exerted is 318.86 N

Explanation:

The force exerted by such a stream is calculated by multiplying the mass flow rate of water by the velocity of the stream of water.

mass flow rate = 21.4 kg/s

velocity = 14.9 m/s

Force exerted = 21.4 kg/s × 14.9 m/s = 318.86 kgm/s^2 = 318.86 N

6 0
3 years ago
Read 2 more answers
The coefficient of cubical expansion of a substance depends upon
zzz [600]
<span>I think that the coefficient of cubical expansion of a substance depends on THE CHANGE IN VOLUME.

Cubical expansion, also known as, volumetric expansion has the following formula:

</span>Δ V = β V₁ ΔT

V₁ = initial volume of the body
ΔT = change in temperature of the body
β = coefficient of volumetric expansion.

β is defined as the <span>increase in volume per unit original volume per Kelvin rise in temperature.
</span>
With the above definition, it is safe to assume that the <span>coefficient of cubical expansion of a substance depends on the change in volume, which also changes in response to the change in temperature. </span>
7 0
3 years ago
A 60 kg skier starts from rest at the top of a frictionless slope of height of 35 meters. The velocity at the bottom is v. If a
Solnce55 [7]

Answer:

Explanation:

Speed of skier without parachute

= √ 2gh

= √ 2 x 9.8 x 35

= 26.2 m / s

Speed of skier with parachute

net force downwards

mg - 200

= 60 x 9.8 -200

= 388 N

acceleration = 388 / 60

a = 6.47 m / s

v = √ 2ah

= √ 2 x 6.47 x 35

= 21.28 m / s

8 0
2 years ago
Read 2 more answers
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