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dmitriy555 [2]
3 years ago
10

you jump out of an airplane at 2000ft and fall 1000ft before opening your parachute (without any forces opposing ) what the spee

d at the time when you open the chute ? ( physics: potencial energy)​
Physics
1 answer:
Dimas [21]3 years ago
4 0

Answer:

Correct answer: V = 78.07 m/s

Explanation:

We can solve this problem combined with the help of kinetics or with energy conservation laws.

The first way is:

This is a free fall with no initial speed (velocity)

The formula for this case is:  V² = 2 g h , we will take that g = 10 m/s²

We must first convert the ft into meters

The relationship is 1 ft = 0.3048 m, according to this 1,000 ft = 304.8 m which is also the height of the fall   h = 304.8 m

V² = 2 · 10 · 304.8 = 6,096 => V = √6,096 = 78.07 m/s

V = 78.07 m/s

Otherwise it cannot be solved because we do not have a mass of parachute jumper.

God is with you!!!

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Answer:

\Delta \theta = 47.57^{\circ} C

Explanation:

given,

moles of air compressed, n = 1.70 mol

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\dfrac{\Delta U}{\Delta t} = \dfrac{\Delta Q}{\Delta t}- \dfrac{\Delta W}{\Delta t}

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\dfrac{\Delta U}{\Delta t} = 6.2 kW

we know,

\dfrac{\Delta U}{\Delta t}=\dfrac{nC_v\Delta \theta}{\Delta t}

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now,

\Delta \theta = \dfrac{\Delta U}{\Deta t}\times \dfrac{\Delta t}{n C_v}

\Delta \theta = 6.2\times 10^3 \times \dfrac{0.273}{1.7\times 20.93}

\Delta \theta = 47.57^{\circ} C

the temperature change per compression stroke is equal to 47.57°C.

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