We are given total 10 tree seedlings.
Number of workshops = 2.
Here order doesn't matters.
<em>When order doesn't matters we apply combination.</em>
We know formula of combination:
For the given situation, we have
n=10 and r=2.
Plugging values in formula, we get
<h3>Therefore, 45 different ways can the nursery give out seedlings.</h3>
Total number of bulbs = 64
Number of defective bulbs = 10
Number of good bulbs = 64 - 10 = 54
P(5 good bulbs) = (54/64)⁵ = (27/32)⁵ = 0.428
Answer: 0.428
Answer: AB = 6
Step-by-step explanation:
If CD = 12 , AC also = 12
B is the midpoint of AC so one side = 6
AB is one side of AC , so AB = 6
I am not a professional, I am simply using prior knowledge!
Note- It would mean the world to me if you would mark me brainliest!
I believe the answer would be angle O.
All you do to find this answer is rotate the 2nd figure so it matches the 1st one above it, and look to see which angles...I guess are where and which match each other.
