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Alex17521 [72]
3 years ago
14

Three planes that intersect in one line

Mathematics
1 answer:
guapka [62]3 years ago
5 0
They are collinear points and are called planes. 
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Yeah his answer is correct Good job!
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Assume you have applied for two scholarships, a Merit scholarship (M) and an Athletic scholarship (A). The probability that you
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NEED HELP WILL MARK BRAINIEST!
Illusion [34]

Answer:

A) 23+5=28

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3 years ago
Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
2 years ago
Please only answer if you 100% sure! Giving brainliest!!
makvit [3.9K]
I believe the first question is B:advertisement

I believe the second question is C: mass-media

I believe the third question is D: all of these are correct

I believe the fourth question is D: incentive

I believe the fifth question is A: it is free of bias


Hope this helps you have a great day!!!!!!
3 0
2 years ago
Read 2 more answers
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