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lutik1710 [3]
3 years ago
7

Please answer!! THIS IS ALL THE POINTS I HAVE LEFT SINCE NOBODY IS ANSWERING MY OTHER QUESTIONS :(

Mathematics
2 answers:
sweet [91]3 years ago
8 0

Answer: Well I will try to answer it

Step-by-step explanation:

A. I would say that the height of the base of the parallelogram its related to the circle since the base have the SAME shape of the circle. The height goes from the circumference to the point of any section of the circle and the radius well, it's the same.

B. I'm not so sure sorry

Art [367]3 years ago
3 0

Answer:

The height of the parallelogram relates to the height of the circle because it is equal to the radius of the circle. The height goes from the circumference to the point of any section of the circle. I hope this helps.

Step-by-step explanation:

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A cargo grain leaves Chicago at noon travelling west at 120 km/h. At 2 pm, a passenger train leaves Chicago travelling east at 3
AfilCa [17]

Answer:

a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km                    

Now, we can find the time when the trains will be 1520 km apart:

1520 km = (x_{1} + 240 km) + x_{2}      

Where 1 is for the cargo train and 2 is for the passenger train.

1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}      

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

1520 km = (v_{1}*t + 240 km) + v_{2}t              

t = \frac{1520 km - 240 km}{120 km/h + 360 km/h} = 2.667h

For the cargo train, it will be 1520 km apart from the passenger train at:

t_{1} = 12 pm + 2 h + 40 min = 2:40 pm

And for a passenger train, it will be 1520 km apart from the cargo train at:

t_{2} = 2 pm + 2 h + 40 min = 4:40 pm  

Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.  

b) The distance traveled by both trains is given by:

x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km    

x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km    

Therefore, at that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

I hope it helps you!        

5 0
2 years ago
Which function below is the inverse of f(x)= 3x+5/7
Ipatiy [6.2K]
Inverse
replace f(x) wih y
solve for x
replace x with f⁻¹(x) and y with x

so

f(x)=3x+5/7
replace
y=3x+5/7
solve for x
minnus 5/7 both sides
y-5/7=3x
divide both sides by 3
\frac{y- \frac{5}{7} }{3}=x
replace with f⁻¹(x)

f⁻¹(x)=\frac{y- \frac{5}{7} }{3}
5 0
3 years ago
Read 2 more answers
What is answer to this equation 7x-4=2
Inga [223]
7x=2+4
7x=6
X=6/7 ans
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3 0
3 years ago
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A racing car used 255 litres of fuel to complete a 340km race.on average,how many litres of fuel did the car use every 100km?
KIM [24]
X=(255÷340)×100
x=0.75×100
x=75
5 0
2 years ago
Mr. Sweeney's car can travel 195 miles on 10 gallons of gas. How far
VikaD [51]

Answer:

Miles in 10 gallons = 195

Miles in 1 gallon = 195/10 = <u>1</u><u>9</u><u>.</u><u>5</u>

Miles in 18 gallons = 19.5 × 18 = <u>3</u><u>5</u><u>1</u><u> </u><u>miles</u><u>.</u>

6 0
2 years ago
Read 2 more answers
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