Answer:
The standard form of the equation is 2x + 5y = -1
Step-by-step explanation:
To find this equation in standard form, we first need to find the slope of the line. We can do that by using the slope formula with the two points.
m(slope) = (y2 - y1)/(x2 - x1)
m = (1 - -3)/(-3 - 7)
m = 4/-10
m = -2/5
Now that we have the slope, we can use that along with the point in point-slope form
y - y1 = m(x - x1)
y - 1 = -2/5(x + 3)
Now that we have that, we can solve for the constant and rationalize the denominators.
y - 1 = -2/5x - 6/5
2/5x + y - 1 = -6/5
2/5x + y = -1/5
2x + 5y = -1
Make a table with the angle theta as independent variable and the radius r as dependent variable:
theta radius = 4+2cos theta radius
------- -----------------------------------------
0 4+2 6
pi/6 4+2cos pi/6 = 4+2(sqrt(3)/2
Perhaps you have already plotted this using webassign (but remember that you have not shared an illustration here). (Please don't type "webassign plot" repeatedly, as it accomplishes nothing.)
Generally, when one wishes to find the area of a region defined by polar functions (as is the case here), one first determines suitable limits of integration from the finished curve and checks them through actual integration.
Which formula should you use to find the area: Look up "areas in polar coordinates," as I did. The formula is as follows:
Enclosed area = Integral from alpha to beta of (1/2)r^2 d(theta). Note that the initial radius here is 6 (since r = 4 plus 2 cos theta is 4+2 when theta = 0).
Answer:
42 = (3 +x)(4 +x)
Step-by-step explanation:
The only equation that has the existing dimensions <em>increased</em> by x is the first one.
Answer:
4.64
Step-by-step explanation:
if you add 2.64 and 2 you get 4.64
