I need to know how to do this last problem

The landscaper charges a rate of $40 per hour to plant trees.Amelia paid a total of $725 for the trees and for the landscaper to

pickupchik [31]

23.5 hours is the anser yeteressdfdsfsjufrhhmrgijfjfxkjvnrtjeigrjiegre

8 0

3 years ago

A cylinder has a base radius of 7m and a height of 14m. What is its volume in cubic m, to the nearest tenths place?

Westkost [7]

Answer:Answer:

2155.1 m^3

Step-by-step explanation:

area= pi* r ^2 * h =pi * 7^2 *14 = 2155.1 m^3

6 0

2 years ago

Show work to triangles 2 and 3 explaining why they are right triangles

olganol [36]

Answer:

Step-by-step explanation:

In order for a triangle to be a right triangle, it has to fit into Pythagorean's Theorem:

$a^2+b^2=c^2$ where c is the hypotenuse.

We need to figure out which is the longest side in each of those triangles and that is the hypotenuse.

In the first set, the sqrt of 443 is 21.04, but that is not the longest side; 24 is. So the Theorem formula for that is:

$\sqrt{443}^2+17^2=24^2$ which gives us

443 + 289 = 576, but 732 does not equal 576, so that one is not right.

In the second set, the sqrt of 725 is the longest side, so that formula is:

$\sqrt{725}^2=14^2+23^2$ which gives us

725 = 196 + 529, and 725 does equal 725, so that one is right.

In the third set, the sqrt of 890 is the longest side, so:

$\sqrt{890}^2=19^2+23^2$ , which gives us

890 = 361 + 529, and 890 = 890, so that is a right triangle as well. That's how you know those are right, compared to the first one that is not.

6 0

3 years ago

Find the slope of the line through the points -12, 10 and -9,-15

Pavlova-9 [17]

Answer:

-25/3

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Which equation represents a graph with a vertex at (–3, 2)?

lesya [120]

We will proceed to find the equations in the vertex form in each case

Part a) $y= 4x^{2}+24x+38$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-38= 4x^{2}+24x$

Factor the leading coefficient

$y-38= 4(x^{2}+6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-38+36= 4(x^{2}+6x+9)$

$y-2= 4(x+3)^{2}$

$y= 4(x+3)^{2}+2$

the vertex is the point $(-3,2)$

Part b) $y=4x^{2}-24x+38$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-38= 4x^{2}-24x$

Factor the leading coefficient

$y-38= 4(x^{2}-6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-38+36= 4(x^{2}-6x+9)$

$y-2= 4(x-3)^{2}$

$y= 4(x-3)^{2}+2$

the vertex is the point $(3,2)$

Part c)  $y=4x^{2}+12x+2$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-2= 4x^{2}+12x$

Factor the leading coefficient

$y-2= 4(x^{2}+3x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-2+9= 4(x^{2}+3x+2.25)$

$y+7= 4(x+1.5)^{2}$

$y= 4(x+1.5)^{2}-7$

the vertex is the point $(-1.5,7)$

Part d) $y=4x^{2}+16x+13$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-13= 4x^{2}+16x$

Factor the leading coefficient

$y-13= 4(x^{2}+4x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-13+16= 4(x^{2}+4x+4)$

$y+3= 4(x+2)^{2}$

$y= 4(x+2)^{2}-3$

the vertex is the point $(-2,-3)$

therefore

the answer is

$y= 4x^{2}+24x+38$

3 0

3 years ago

Read 2 more answers