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2 years ago

Solve the system of equations a+s=560 8a+3s=2905

Mathematics

1 answer:

Rasek [7]1 year ago

4 0

Answer:

a=245 s=315

Step: Solve a+s=560 for a:

a+s=560

a+s=560(Add -s to both sides)

a=−s+560

Step: Substitute −s+560 for a in 8a+3s=2905:

8a+3s=2905

8(−s+560)+3s=2905

−5s+4480=2905(Simplify both sides of the equation)

−5s+4480=2905(Add -4480 to both sides)

−5s=−1575

−5s=−1575(Divide both sides by -5)

s=315

Step: Substitute 315 for s in a=−s+560:

a=−s+560

a=−315+560

a=245

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