Answer:
-8 is not a solution to the inequality
Step-by-step explanation:
Answer:
Gray family's sprinkler was used for 40 hours.
Thompson family's sprinkler was used for 35 hours.
Step-by-step explanation:
The Gray family and the Thompson family each used their sprinklers last summer.
Let x= amount of time in hours that the Gray family's sprinkler was used.
Let y = amount of time in hours that the Thompson family's sprinkler was used.
The water output rate for the Gray family's sprinkler was 40 L per hour. The water output rate for the Thompson family's sprinkler was 20 L per hour. This means that the combined number of hours that both family's used their sprinklers is 40x + 20y
The families used their sprinklers for a combined total of 75 hours, resulting in a total water output of 2300 L .
This means
x + y = 75
40x + 20y = 2300 - - - - - - - -1
Substituting x = 75 -y into equation 1,
40 ( 75 - y ) + 20y = 2300
3000 - 40y + 20y = 2300
-40y + 20y = 2300 - 3000
-20y = -700
y = 700/20 = 35 hours
x = 75 - y
x = 75 -35 = 40 hours
Answer:
3!2!/5! or 3/5 x 2/4 x 1/3 either way it makes 6/60 = 1/10
Answer:
232 square feet
Step-by-step explanation:
The outside dimensions of the yard are 26 ft by 36 ft, so its total area is ...
yard including walk = (26 ft)(36 ft) = 936 ft²
The dimensions of the yard inside the walkway are 22 ft by 32 ft, so that area is ...
yard not including walk = (22 ft)(32 ft) = 704 ft²
The difference in these areas is the area of the walkway:
walkway area = (yard including walk) - (yard not including walk)
= (936 -704) ft² = 232 ft² . . . . area of the walk
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Another way to figure this is to consider the length of the centerline of the walkway. That is the perimeter of a rectangle that is 24 ft by 34 ft. The perimeter (centerline length) is 116 ft, and the width of the walk is 2 ft, so its area is ...
(116 ft)(2 ft) = 232 ft²
a ray is a line with a single endpoint
