Answer:
"sing" that is the answer
Explanation:
Answer:
REad from slide and speak clearly and slowy.
Explanation:
Answer:
use loop
for(int i =10;i>2; i--)
{
System.out.println(i+"\n")
}
Answer:
x(t) = −2 cos (
−
) + 4 cos (
)
Explanation:
Given:
Fundamental period of real valued continuous-time periodic signal x(t) = T = 8
Non-zero Fourier series coefficients for x(t) :
a₁ =
= j
a₅ =
= 2
To find:
Express x(t) in the form
∞
x(t) = ∑ A
cos ( w
t + φ
)
Solution:
Compute fundamental frequency of the signal:
w₀ = 2 π / T
= 2 π / 8 Since T = 8
w₀ = π / 4
∞
∑ 
x(t) = k=⁻∞
=
= 
= −2 sin (
) + 4 cos (
)
= −2 cos (
−
) + 4 cos (
)