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irina [24]
3 years ago
7

Where are the instructions stored that the computer needs when it is switched on?

Computers and Technology
1 answer:
WARRIOR [948]3 years ago
4 0
This is stored in the ROM (Read Only Memory)
I believe that is the answer, all i can come up with.
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After class a student asked why you would ever use a heap instead of a binary search tree. Provide a good explanation for why an
sertanlavr [38]

Answer:

Heap is useful when you want to find max/min element in the given list

BinarySearchTree is used if you need sorted elements of the list

Explanation:

Heap is Good at finding Min/Max and it's time complexity is  (O(1)), while BST is good at all finds (O(logN)). Insert is O(logN) for Heap and BSTstructures..

Max Heap ensures that elements on higher levels are greater than elements at lower level

MinHeap ensures that elements on higher levels are lesser than elements at lower level

BST gives sorted elements by following order (left,root,right).If we want sorted elements we can go with BST

5 0
3 years ago
Wireless networks usually use ____ signals to send data.
barxatty [35]
<span>Wireless networks usually use radio (b) signals to send data. </span>
6 0
3 years ago
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A student will not be allowed to sit in exam if his/her attendance is less than 75% .
Oxana [17]

Answer:

Sorry, this is too vague to understand as you don’t have any charts, graphs, or anything

Explanation:

6 0
3 years ago
In the game of economics, producers look to technological improvements to increase which of the following?
Vaselesa [24]
They're looking to increase productivity 
7 0
3 years ago
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A cache has been designed such that it has 512 lines, with each line or block containing 8 words. Identify the line number, tag,
Reptile [31]

Answer:

Given address = 94EA6_{16}

tag = 0 * 94  ( 10010100 )

line = 0 * 1 D 4 ( 111010100 )

word position = 0*6 ( 110 )

Explanation:

using the direct mapping method

Number of lines = 512

block size = 8 words

word offset = log ^{8} _{2}  = 3 bit

index bit = log^{512}_{2}  = 9 bit

Tag = 20 - ( index bit + word offset ) = 20 - ( 3+9) = 8 bit

Given address = 94EA6_{16}

tag = 0 * 94  ( 10010100 )

line = 0 * 1 D 4 ( 111010100 )

word position = 0*6 ( 110 )

8 0
4 years ago
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