C2H4(g) + H2O(g) ⇌ C2H5OH

1 answer:

6 0

Molecular wt if ethene = 28 g/mol
take 14 ÷ 28 = 0.5 mol
since there is a 1:1 ratio between ethene and ethanol one should produce 0.5 mol

MW ethanol = 46
0.5 × 46 = 23 g should be produced.

17.25/23 = 0.75 = 75% Percent yield

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