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2 years ago

If Iron (Fe) gained a proton what would it be?

Chemistry

1 answer:

Mkey [24]2 years ago

8 0

If iron (Fe) gained a proton it would become cobalt (CO).

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2. Among the complexes K4[Cr(CN)6] (A),K4[Fe(CN)6] (B) , K3[Co(CN)6] (C) , K4[Mn(CN)6] (D), Jahn-Teller distortion is shown by *

Vanyuwa [196]

Answer:

K4[Cr(CN)6] and K4[Mn(CN)6]

Explanation:

The Jahn–Teller effect, sometimes also known as Jahn–Teller distortion, describes the geometrical distortion of molecules and ions that is associated with certain electron configurations. In Jahn Teller effect, more electrons occupy the lower orbital than the upper one, resulting in an overall lowering of the electronic energy. This distortion is typically observed among octahedral complexes where the two axial bonds can be shorter or longer than those of the equatorial bonds. In octahedral complexes, the Jahn–Teller effect is most pronounced when an odd number of electrons occupy the eg orbitals. This situation is most pronounced in complexes with the configurations d9 , low-spin d7 or high-spin d4. These configurations display a strong Jahn Teller effect. Jahn Teller may also be observed if there is a degeneracy due to the electrons in the t2g orbitals. A weak Jahn Teller effect is also observed for d5 species.

K4[Cr(CN)6] contains Cr^2+ which is a d4 specie, hence it exhibits Jahn Teller effect. Also, K4[Mn(CN)6] contains Mn^2+ which is a d5 specie, therefore it also exhibits Jahn Teller effect.

6 0

3 years ago

The initial activity of 37Ar is 8540 disintegrations per minute. After 10.0 days, the activity is 6990 disintegrations per minut

mylen [45]

Answer:

Approximately 3318 disintegrations per minute.

Explanation:

The activity $A$ of a radioactive decay at time $t$ can be found with the following equation:

$\displaystyle A(t) = A_0 \cdot \mathrm{e}^{-\lambda\cdot t}$ .

In this equation,

$\mathrm{e}$ is the natural base. $\mathrm{e}\approx 2.71828$ .
$A_0$ is the initial activity of the decay. For this question, $A_0 = \rm 8540\; min^{-1}$ .
The decay constant $\lambda$ of this sample needs to be found.

The decay constant here can be found using the activity after 10 days. As long as both times are in the same unit (days in this case,) conversion will not be necessary.

$A(10) = A_0\cdot \mathrm{e}^{\rm -\lambda \times 10\;day}= (\mathrm{8540\; min^{-1}})\cdot \mathrm{e}^{\rm -\lambda \times 10\;day}$ .

$A(10) = \rm 6690\; min^{-1}$ .

$\displaystyle \frac{\rm 6690\; min^{-1}}{\mathrm{8540\; min^{-1}}} = \mathrm{e}^{\rm -\lambda \times 10\;day}$

Apply the natural logarithm to both sides of this equation.

$\displaystyle \ln{\left(\frac{\rm 6690\; min^{-1}}{\mathrm{8540\; min^{-1}}}\right)} = \ln{\left(\mathrm{e}^{\rm -\lambda \times 10\;day}\right)}$ .

$\displaystyle \rm -\lambda \cdot (10\;day) = \ln{\left(\frac{\rm 6690\; min^{-1}}{\mathrm{8540\; min^{-1}}}\right)}$ .

$\displaystyle \rm \lambda= \rm \frac{\displaystyle \ln{\left(\frac{\rm 6690\; min^{-1}}{\mathrm{8540\; min^{-1}}}\right)}}{-10 \; day} \approx 0.0200280\; day^{-1}$ .

Note that the unit of the decay constant $\lambda$ is $\rm day^{-1}$ (the reciprocal of days.) The exponent $-\lambda \cdot t$ should be dimensionless. In other words, the unit of $t$ should also be days. This observation confirms that there's no need for unit conversion as long as the two times are in the same unit.

Apply the equation for decay activity at time $t$ to find the decay activity after 47.2 days.

$\displaystyle \begin{aligned}A(t)& = A_0 \cdot \mathrm{e}^{-\lambda\cdot t}\\&\approx \rm \left(8540\; min^{-1}\right)\cdot \mathrm{e}^{-0.0200280\; day^{-1}\times 47.2\;day}\\&\approx \rm 3318\; min^{-1}\end{aligned}$ .

By dimensional analysis, the unit of activity here should also be disintegrations per minute. The activity after 47.2 days will be approximately 3318 disintegrations per minute.

8 0

3 years ago

What has more atoms, a mole of carbon or a mole of fluorine?

GuDViN [60]

Answer:

They have the same number of atoms

Explanation:

The mole (symbol: mol) is the base unit of amount of substance.

Think of mole meaning like inch. An inch of grass is the same as an inch of a flower. Mole is the standard measuring unit of atoms.

6 0

2 years ago

What is the name of the visible surface of the Sun? (And surface doesn’t imply solid, as this surface’s density is 6000 times lo

Fiesta28 [93]

Answer:

The correct option is: a. Photosphere

Explanation:

Sun is the brightest star in the sky of our planet Earth and the principle component of the Solar System. It is a gaseous object that is made up of hot plasma and contributes 99.86% to the total mass of our Solar System.

The Sun does not have a clearly defined surface. The visible surface of the Sun is known as the Photosphere, which is the deepest visible portion of the Sun.

4 0

3 years ago

How do three states of matter arise?

Evgen [1.6K]

The status of the state of matter of a material defines the phase. Pellet currently case 16 is defined; three of which solid, liquid and gas are referred to as conventional cases. There are a total of 16 state currently defined, these classic except; liquid crystal, amorphous solid, magnetic regularly, superconducting, superfluid, the Bose-Einstein condensation, Rydberg molecules, plasma (ionized gas), the quark-gluon plasma, degenerate matter, Superkate, the stringy liquid and SuperCam mine. Daily life in general, solid materials, include liquid or gaseous, but outside world, 99% of the material in the universe plasma (ionized gas) is in the form.

6 0

3 years ago