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r-ruslan [8.4K]
3 years ago
13

Under the same conditions of temperature and pressure a liquid differs from a gas because the particles of the liquid

Chemistry
2 answers:
MAXImum [283]3 years ago
7 0

Answer:

Have stronger forces of attraction between them

Explanation:

The greater the distance between particles and the smaller the particle size, the smaller the force of attraction. The particles in a gas are further apart than those in a liquid, and so the force of attraction between them is less.

noname [10]3 years ago
6 0

Answer:

liquid has more attraction between molecules. It takes energy to break these forces to change the liquid to a gas.

Explanation:

because liquid has more attraction

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PLEASE HELP!!!!
Verizon [17]
Endothermic or C, if you would like a reason why, do not hestitate to ask
3 0
3 years ago
By the reaction of carbon & oxygen , a mixture of CO &CO2 is obtained. What is the composition by mass of the mixture ob
Hatshy [7]
M(O₂)=20g
M(O₂)=32.0 g/mol
n(O₂)=20/32.0=0.625 mol

m(C)=12 g
M(C)=12.0 g/mol
n(C)=12/12.0=1.0 mol

   2C     +     O₂      →    2CO
1 mol    0.625 mol        1 mol
         0.625-0.5=0.125 mol

      2CO    +         O₂       →        2CO₂
0.250 mol       0.125 mol       0.250 mol

n(CO)=1 mol - 0.250 mol = 0.750 mol
M(CO)=28.0 g/mol
m(CO)=0.750*28.0=21.0 g

n(CO₂)=0.250 mol
M(CO₂)=44.0 g/mol
m(CO₂)=0.250*44.0=11.0 g
4 0
3 years ago
How many Sodium (NA) Atoms are in Methylene?​
postnew [5]

Answer:

No Sodium(Na) in methylene

Explanation:

Methylene is an organic compound

4 0
3 years ago
What is mass in chemistry
alexandr402 [8]

Answer:

mass is a measure of the amount of matter in a sample or object. It is measured in grammes or kilogrammes

8 0
3 years ago
Automobile catalytic converters use a platinum catalyst to reduce air pollution by changing emissions such as carbon monoxide, C
julia-pushkina [17]

Answer: 448 g of O_2 will be required to completely react with 784g moles of CO(g) during this reaction.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} CO=\frac{784g}{28g/mol}=28moles

The balanced chemical equation is:

2CO(g)+O_2(g)\rightarrow 2CO_2(g)  

According to stoichiometry :

2 moles of CO require  = 1 mole of O_2

Thus 28 moles of CO will require=\frac{1}{2}\times 28=14moles  of O_2

Mass of O_2=moles\times {\text {Molar mass}}=14moles\times 32g/mol=448g

Thus 448g of O_2 will be required to completely react with 784g moles of CO(g) during this reaction.

6 0
3 years ago
Read 2 more answers
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