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strojnjashka [21]
3 years ago
9

Does someone know this answer? Estimate the quotient by rounding the expression 432 ÷ 73 ≈ _____

Mathematics
2 answers:
RideAnS [48]3 years ago
7 0

Answer:

6

Step-by-step explanation:

432 ÷ 73 ≈ 5.917

So round to 6

leonid [27]3 years ago
3 0
5.917
5 or higher you round to the next value so 9 is greater than 5 which would make the whole value 6
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Which of the following sets of values correctly completes the t-chart for the equation y = 2x2 - 1.
natali 33 [55]

Answer:

The sets of values that correctly completes the t-chart are:

7, -1, 7

Hence, option B is true.

Step-by-step explanation:

Given the equation

y = 2x² - 1

FOR x = -2

substitute x = -2 in the equation

y = 2x² - 1

y = 2(-2)² - 1

y = 8 - 1

y = 7

FOR x = 0

substitute x = 0 in the equation

y = 2x² - 1

y = 2(0)² - 1

y = -1

FOR x = 2

substitute x = 2 in the equation

y = 2x² - 1

y = 2(2)² - 1

y = 8 - 1

y = 7

Thus, the t-chart becomes:

x              y

-2            7

0             -1

2              7

Thus, the sets of values that correctly completes the t-chart are:

7, -1, 7

Hence, option B is true.

7 0
3 years ago
What is the standard form of five and three hundred fifty two thousands
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The number "seven hundred and four thousand, six hundred and twenty" is written as 704,620 in numeric or standard form.<span> In converting a number expressed in words to numerals, it is important to write each digit in its proper place value.</span>
7 0
3 years ago
Matrices A and B are square matrices of the same size. Prove Tr(c(A + B)) = C (Tr(A) + Tr(B)).
alexira [117]

Answer with Step-by-step explanation:

We are given that two matrices A and B are square matrices of the same size.

We have to prove that

Tr(C(A+B)=C(Tr(A)+Tr(B))

Where C is constant

We know that tr A=Sum of diagonal elements of A

Therefore,

Tr(A)=Sum of diagonal elements of A

Tr(B)=Sum of diagonal elements of B

C(Tr(A))=C\cdot Sum of diagonal elements of A

C(Tr(B))=C\cdot Sum of diagonal elements of B

C(A+B)=C\cdot (A+B)

Tr(C(A+B)=Sum of diagonal elements of (C(A+B))

Suppose ,A=\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]

B=\left[\begin{array}{ccc}1&1\\1&1\end{array}\right]

Tr(A)=1+1=2

Tr(B)=1+1=2

C(Tr(A)+Tr(B))=C(2+2)=4C

A+B=\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]+\left[\begin{array}{ccc}1&1\\1&1\end{array}\right]

A+B=\left[\begin{array}{ccc}2&1\\2&2\end{array}\right]

C(A+B)=\left[\begin{array}{ccc}2C&C\\2C&2C\end{array}\right]

Tr(C(A+B))=2C+2C=4C

Hence, Tr(C(A+B)=C(Tr(A)+Tr(B))

Hence, proved.

5 0
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Bad White [126]

Answer:

Step-by-step explanation:

x=2

y=3

z=4

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