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4 years ago

Howard cuts 80 centimeters off a 1.5-meter board. how much of the board does howard have left?

Mathematics

2 answers:

Paha777 [63]3 years ago

8 0

80 centimeters off a 1.5 meter board. How much of the board does Howard have left

chubhunter [2.5K]4 years ago

4 0

Howard has 42 cm of the board left.

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The compound amount is $…The amount of interest earned is $…

nadya68 [22]

In order to calculate the compound amount and the amount of interest earned, we can use the formula below:

$A=P\cdot(1+\frac{i}{n})^{nt}$

Where A is the compound amount after t years, P is the principal (initial amount) i is the interest rate and n is how many times the interest is compounded in a year.

So, for P = 71000, i = 0.0102, t = 4 and n = 4, we have:

$\begin{gathered} A=71000\cdot(1+\frac{0.0102}{4})^{4\cdot4}_{} \\ A=71000\cdot(1+0.00255)^{16} \\ A=73952.87 \end{gathered}$

Therefore the compound amount is $73952.87

The amount of interest is:

$\begin{gathered} I=A-P \\ I=73952.87-71000 \\ I=2952.87 \end{gathered}$

So the amount of interest earned is $2952.87.

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2 years ago

Electrical energy (E) is measured in kilowatt hours (kwh) using the formula E = P · t, where P is the power in kilowatts and t i

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Kilowatts of power are used each hour
104/13=8

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3 years ago

Two sides of a triangle measure 25 cm and

julia-pushkina [17]

First one I believe

6 0

3 years ago

The question is <br> 8x+tx=r <br> What you wanna solve for is x

ella [17]

Answer:

x = r/(8+t)

Step-by-step explanation:

8x + tx = r

Using distributive property,

x(8+t) = r

Divide by 8+t on both sides,

x = r/(8+t)

3 0

3 years ago

Explain me PLEASEEEE!!!

kirza4 [7]

Answer:

$\frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}=\frac{1}{a^{7}}$

Step-by-step explanation:

Let us revise the properties of exponents

$a^{m}.a^{n}=a^{m+n}$

$\frac{a^{m}}{a^{n}}=a^{m-n}$

$(a^{m})^{n}=a^{m.n}$

$a^{-m}=\frac{1}{a^{m} }$

Let us use these properties to solve the question

→ By using the 3rd property above

∵ $(a^{2})^{3}=a^{2.3}=a^{6}$

∴ $\frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10} }$

→ By using the 1st property above

∵ $a^{6}.a^{-3}=a^{6+-3}=a^{6-3}=a^{3}$

∴ $\frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}$

→ By using the 2nd property above

∵ $\frac{a^{3}}{a^{10}}=a^{3-10}=a^{-7}$

∴ $\frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}$

→ By using the 4th property above

∵ $a^{-7}=\frac{1}{a^{7}}$

∴ $\frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}=\frac{1}{a^{7}}$

8 0

3 years ago