The coach of a soccer team is holding tryouts and can only take 3 more players. There are 6 players trying out. How many differe

nt groups of 3 players could possibly be chosen?

1 answer:

5 0

$C(6,3)=\dfrac{6!}{3!3!}=\dfrac{4\cdot5\cdot6}{2\cdot3}=20$

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