The coach of a soccer team is holding tryouts and can only take 3 more players. There are 6 players trying out. How many differe

nt groups of 3 players could possibly be chosen?

Mathematics

1 answer:

Elena-2011 [213]3 years ago

5 0

$C(6,3)=\dfrac{6!}{3!3!}=\dfrac{4\cdot5\cdot6}{2\cdot3}=20$

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scZoUnD [109]

Answer:

π = S/2πrh
v = √2E/m
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Step-by-step explanation:

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