Y = (2/3).x - 6. If y=0, then 0= (2/3).x - 6. Solve for x:
2x/3 - 6 = 0
Same denominator:
(2x - 18)/3 = 0
2x - 18 = 0
2x = 18 and x = 9 (x-coordinate)
<h2><u>Circle Equations</u></h2>
<h3>Write the standard form of the equation of the circle with the given characteristics.</h3><h3>Center: (0, 0); Radius: 2</h3>
To determine the equation of a circle, use the standard form of a circle (x - h)² + (y - k)² = r² where,
- <u>(h, k)</u> is the center; and
- <u>r</u> is the radius
Substitute the values of the center and radius to the standard form.
<u>Given:</u>
<u>(0, 0)</u> - <u>center</u>
<u>2</u> - <u>radius</u>
- (x - h)² + (y - k)² = 2²
- (x - 0)² + (y - 0)² = 4
- x² + y² = 4
<u>Answer:</u>
- The equation of the circle is <u>x² + y² = 4</u>.
Wxndy~~
Answer:
Step-by-step explanation:
The intersection is when both functions have same coordinates
Substitute to get
- - 2x + 16 = 4x + 10
- 4x + 2x = 16 - 10
- 6x = 6
- x = 1
The y- coordinate is
- y = - 2(1) + 16 = -2 + 16 = 14
So the intersection point is (1, 14)
