Identify the zero(s) of
x)=4x^{2} - 20x - 56" alt="f(x)=4x^{2} - 20x - 56" align="absmiddle" class="latex-formula">. -- Urgent 10 minutes! Many points!
1 answer:
Answer:
x = - 2, x = 7
Step-by-step explanation:
Given
f(x) = 4x² - 20x - 56
To find the zeros let f(x) = 0, that is
4x² - 20x - 56 = 0 ( divide through by 4 )
x² - 5x - 14 = 0 ← in standard form
(x - 7)(x + 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
x - 7 = 0 ⇒ x = 7
You might be interested in
The width of the garden is 78
You just divide 7722 by 99 (which is 78)
10, 20w, 2w, and we are factors of 20w and 40wz
Sqrt55. Use the pythagorean theorem; 3^2 + x^2 = 8^2
Answer:
120
Step-by-step explanation:
yw dude
Answer:
Step-by-step explanation:
It was 12 take away 210 add 20 to 3243