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never [62]
2 years ago
9

Identify the zero(s) of

x)=4x^{2} - 20x - 56" alt="f(x)=4x^{2} - 20x - 56" align="absmiddle" class="latex-formula">. -- Urgent 10 minutes! Many points!
Mathematics
1 answer:
AURORKA [14]2 years ago
5 0

Answer:

x = - 2, x = 7

Step-by-step explanation:

Given

f(x) = 4x² - 20x - 56

To find the zeros let f(x) = 0, that is

4x² - 20x - 56 = 0 ( divide through by 4 )

x² - 5x - 14 = 0 ← in standard form

(x - 7)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x - 7 = 0 ⇒ x = 7

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