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never [62]
3 years ago
9

Identify the zero(s) of

x)=4x^{2} - 20x - 56" alt="f(x)=4x^{2} - 20x - 56" align="absmiddle" class="latex-formula">. -- Urgent 10 minutes! Many points!
Mathematics
1 answer:
AURORKA [14]3 years ago
5 0

Answer:

x = - 2, x = 7

Step-by-step explanation:

Given

f(x) = 4x² - 20x - 56

To find the zeros let f(x) = 0, that is

4x² - 20x - 56 = 0 ( divide through by 4 )

x² - 5x - 14 = 0 ← in standard form

(x - 7)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x - 7 = 0 ⇒ x = 7

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Please help me with my math hw
nydimaria [60]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Problem 1</u>

<u />\frac{3}{4}x=60\\ \\\frac{3}{4}x*4=60*4\\ \\3x=240\\\\\frac{3x}{3}=\frac{240}{3}\\ \\ x=80


Check solution:

\frac{3}{4}(80)\stackrel{?}{=}60\\\\\frac{3*80}{4}\stackrel{?}{=}60\\\\\frac{240}{4}\stackrel{?}{=}60\\\\60=60

<u>Problem 2</u>

<u />\frac{2}{5}x=42\\ \\\frac{2}{5}x*5=42*5\\ \\2x=210\\\\\frac{2x}{2}=\frac{210}{2}\\ \\ x=105

Check solution:

\frac{2}{5}(105)\stackrel{?}{=}42\\\\\frac{2*105}{5}\stackrel{?}{=}42\\ \\\frac{210}{5}\stackrel{?}{=}42\\ \\42=42

<u>Problem 3</u>

<u />\frac{3}{5}y=40\\ \\\frac{3}{5}y*5=40*5\\ \\3y=200\\\\\frac{3y}{3}=\frac{200}{3}\\ \\ y=\frac{200}{3}

Check solution:

\frac{3}{5}(\frac{200}{3})\stackrel{?}{=} 40\\ \\ \frac{3*200}{5*3}\stackrel{?}{=} 40\\ \\\frac{600}{15}\stackrel{?}{=}40\\\\40=40

<u>Problem 4</u>

<u />-\frac{8}{3}m=6\\\\-\frac{8}{3}m*3=6*3\\ \\-8m=18\\\\\frac{-8m}{-8}=\frac{18}{-8}\\\\m=-\frac{18}{8}\\ \\m=-\frac{9}{4}

Check solution:

-\frac{8}{3}(-\frac{9}{4})\stackrel{?}{=}6\\\\\frac{-8*-9}{3*4}\stackrel{?}{=}6\\\\\frac{72}{12}\stackrel{?}{=}6\\ \\6=6

<u>Problem 5</u>

<u />\frac{5}{6}x=4\\ \\\frac{5}{6}x*6=4*6\\ \\5x=24\\\\\frac{5x}{5}=\frac{24}{5}\\ \\ x=\frac{24}{5}

Check solution:

\frac{5}{6}(\frac{24}{5})\stackrel{?}{=}4\\ \\\frac{5*24}{6*5}\stackrel{?}{=}4\\\\\frac{24}{6}\stackrel{?}{=}4\\ \\4=4

<u>Problem 6</u>

<u />\frac{5}{3}x=12\\ \\\frac{5}{3}x*3=12*3\\ \\5x=36\\\\\frac{5x}{5}=\frac{36}{5}\\ \\x=\frac{36}{5}

Check solution:

\frac{5}{3}(\frac{36}{5})\stackrel{?}{=}12\\\\\frac{5*36}{3*5}\stackrel{?}{=}12\\ \\\frac{36}{3}\stackrel{?}{=}12\\ \\12=12

7 0
2 years ago
Select the property of equality used to arrive at the conclusion. If x = 4, then 5x = 20 the addition property of equality the m
shtirl [24]

Answer:

The Division Property of Equality

Step-by-step explanation:

<u>The Addition Property of Equality:</u> When you add something to one side of the equation, you must add the same thing to the other side.

<u>The Subtraction Property of Equality:</u> When you subtract something from one side of the equation, you must subtract the same thing from the other side.

<u>The Multiplication Property of Equality:</u> When you multiply something to one side of the equation, you must multiply the same thing to the other side.

<u>The Division Property of Equality:</u> When you divide something from one side of the equation, you must divide the same thing from the other side.

In this case, you have to divide both sides of the equation by 5 to get x = 4. That means that the division property of equality was used.

I hope this helps! Have a great day!

8 0
3 years ago
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10. The parent teacher association is raising money
Mumz [18]

Answer:

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4 0
3 years ago
Find the area of the larger sector.
Wewaii [24]

Step-by-step explanation:

the formula for the area of a sector is

(x°(r^2)π)/360

with x being the angle

r bring the radius of the circle

(255(13.4)^2π)/360

399.6

Hope that helps :)

3 0
3 years ago
If the average (arithmetic mean) of four different numbers is 30, how many of the numbers are greater than 30 ?
IrinaVladis [17]

Answer:

Maximum 3 numbers. Minimum 1 number.

Step-by-step explanation:

Well, let us look at the case when 3 numbers are greater than 30. Let us take numbers as 1, 2, 3 and 114 and find their mean which is (1+2+3+114)/4=30.

Now let us look at the case in which 2 numbers greater than 30. Let us take numbers 28, 29, 31 and 32 and find their mean which is (28+29+31+32)/4=30.

Now let us look at the case in which 1 number greater than 30. Let us take numbers 27, 28, 29 and 36 and find their mean which is (27+28+29+36)/4=30.

So it can be concluded that maximum 3 numbers and minimum 1 number are greater than 30.

6 0
3 years ago
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