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Cerrena [4.2K]
3 years ago
11

What is the answer I don't know hat it is

Mathematics
1 answer:
Aleksandr [31]3 years ago
4 0
The answer would be 3x-4=2x+7 or D.
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Help pls ASAP I’ll help u in return!!!!!!
Ad libitum [116K]

X/y=4

You can put it as:

y=1/4.x

Hope you get it!

4 0
4 years ago
Area for a rectangle with two semi circles
AlexFokin [52]
Do you have anymore information on the rectangle?
5 0
3 years ago
Missy did this work to solve an equation. Did she make an error?
STatiana [176]

Answer: yes, she did made an error, a very big mistake.

Step-by-step explanation:

first, we have varieties of ways in which we can use to solve this, the most important thing is to stick to the mathematical rules of solving any equations.

using the most simpler method

-4x + 11 = 6x + 1

collect like ter

-4x -6x = 1 - 11

-10x = -10

divide bothside by -10

-10x/-10 = -10/-10

x=1

secondly, using the method she is intending to use, its more easier to subtract 6x from bothside

-4x + 11 = 6x +1

-6x -6x

_______________

-10x + 11 = 1

-10x = 1-11

-10x = -10

x = 1

or still we can doing it exactly as she did, but it will take us through a long way i.e by adding +6

-4x + 11 = 6x + 1

+6x +6x

_______________

2x +11 = 12x +1

2x-12x = 1-11

-10x=-10

x=1

4 0
3 years ago
Read 2 more answers
Help please and Thankyou
dalvyx [7]

Answer: not correct reset an-[ERROR]

Step-by-step explanation:

3 0
3 years ago
Factorise:<br>vii)p^2+14p+13<br>Please help me....​
tiny-mole [99]

Answer:

(p+13)(p+1)

Step-by-step explanation:

p² + 14p + 13

we want to find two numbers that add to 14 and multiply to 13

we can start looking by listing the factors of 13

we get 13 and 1 and -13 and -1

13 and 1 multiply to 13 ( 13 × 1 = 13 ) and add to 14 ( 13 + 1 = 14 )

-13 and -1 multiply to 13 ( -13 × -1 = 13 ) and add to -14 ( -13 + -1 = -14 )

the two numbers that would add to 14 and multiply to 13 would be 13 and 1

now we can factor out the two numbers from 14 and split the p from p² to get (p+13)(p+1)

and we are done

4 0
2 years ago
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