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Degger [83]
3 years ago
14

In which quadrant is sec e< 0 and tan e > 0?

Mathematics
1 answer:
iren2701 [21]3 years ago
7 0

Answer:

C

Step-by-step explanation:

Because Tangent is positive in third quadrant

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O número 2021 tem resto 5 quando dividido pelo nmr 6, 7, 8, e pelo nmr 9. Quantos múmeros inteiros positivos menores do que 2021
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336

Step-by-step explanation:

2021-5=2016÷6=336

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-3 + n = 6n + 22 ; Solve for n.
anygoal [31]

Answer:

-3 + n = 6n + 22

-1n on both sides

-3=5n+22

-22 on both sides

-25=5n

divided by 5

-5=n

Step-by-step explanation:

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Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is
Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

p=\dfrac{2}{3}

q=\dfrac{1}{3}

Now,

P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111

Hence, a) 0.2222, b) 0.3292, c) 0.1111

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Step-by-step explanation:

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3 years ago
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