Answer:
Yes, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66
Step-by-step explanation:
H0 : σ² = 2.66²
H1 : σ² < 2.66²
X²c = (n - 1)*s² ÷ σ²
sample size, n = 40
Sample standard deviation, s = 1.9
X²c = ((40 - 1) * 1.9²) ÷ 2.66²
X²c = 140.79 ÷ 7.0756
X²c = 19.897
Using a confidence level of 95%
Degree of freedom, df = n - 1 ; df = 40 - 1 = 39
The critical value using the chi distribution table is 25.6954
Comparing the test statistic with the critical value :
19.897 < 25.6954
Test statistic < Critical value ; Reject the Null
Hence, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66
Answer:
Step-by-step explanation:
y + 5 = -1/2(x - 4)
y + 5 = -1/2x + 2
y = -1/2x - 3
Answer:
B is correct. Your starting amount is 210$ And you're taking away 15$ each time she uses the club,x.
Step-by-step explanation:
Answer:
The linear function model the situation is b = 210 - 15x .
Option (B) is correct .
Step-by-step explanation:
Let us assume that the number of times giselle uses the club be x .
As given
giselle pays $210 in advance on her account at the athletic club.
Each time she uses the club,$15 is deducted from the account.
Let suppose that the money left after giselle uses the club x times is b .
Than the equation becomes
Money left = Amount pay in advance - Deducted amount × Number of times giselle uses the club .
Put all the values in the above
b = 210 - 15 × x
b = 210 - 15x
Therefore the linear function model the situation is b = 210 - 15x .
Option (B) is correct .
If it has a constant slope that means it makes a straight line making it linear
The answer would be 5.79
Hope I helped :)