Damiel sold 12 more cds on the 7th day than the average over the first 6 days. to show work find the mean(average) of the 6 numbers. and subyract that from 25.
The minimum surface area that such a box can have is 380 square
<h3>How to determine the minimum surface area such a box can have?</h3>
Represent the base length with x and the bwith h.
So, the volume is
V = x^2h
This gives
x^2h = 500
Make h the subject
h = 500/x^2
The surface area is
S = 2(x^2 + 2xh)
Expand
S = 2x^2 + 4xh
Substitute h = 500/x^2
S = 2x^2 + 4x * 500/x^2
Evaluate
S = 2x^2 + 2000/x
Differentiate
S' = 4x - 2000/x^2
Set the equation to 0
4x - 2000/x^2 = 0
Multiply through by x^2
4x^3 - 2000 = 0
This gives
4x^3= 2000
Divide by 4
x^3 = 500
Take the cube root
x = 7.94
Substitute x = 7.94 in S = 2x^2 + 2000/x
S = 2 * 7.94^2 + 2000/7.94
Evaluate
S = 380
Hence, the minimum surface area that such a box can have is 380 square
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The theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
According to the given question.
A card is drawn from a shuffled standard deck.
Since, the total number of cards in a shuffled standard deck = 52
And, the total number of aces in a shuffled standard deck = 4
As, we know that "the theoretical probability of an event is the number of desired outcomes divided by all possible outcomes".
Therefore, the theoretical probabability of drawing an ace from a shuffled deck of playing cards
= 4/52
= 1/13
Hence, the theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
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you need to add for number one you need to subtract for number two you need to add for number 3 you need to subtract for number 4
