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3 years ago

Multiply the ones 472×7

1 answer:

3 0

The answer you will get is 3304, and in order to get this, you could use a simple step which is adding, so we would do 472 + 472 + 472 + 472 + 472 + 472 + 472, which gives you 3304. Adding is much faster and easier way to do it to get your answer.

Hope this helped!

Nate

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Last years average ticket price was £22 this year the average ticket price has increased by 5% what is the average price now

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2 years ago

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1. A clerk is paid P 45.25 per hour for 40 hours a week, 1.50 times the

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The clerk's total earnings is P520.375

Step-by-step explanation:

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Overtime Earnings = 1.5 * P45.25

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Holiday Earnings for 2 hours = P181.0

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Total = Overtime Earnings for 5 hours + Holiday Earnings for 2 hours

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3 years ago

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The highest weekly wage of a group

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2 years ago

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Match the cofactors to their corresponding entries in the matrix.

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Answer:

The co-factors and their values are shown in the table below.

Step-by-step explanation:

We are given the matrix, $\begin{bmatrix}3&7&1\\7&1&-3\\8&5&1\end{bmatrix}$ .

It is required to match the co-factors with the corresponding values.

As, the co-factors are given by,

$A_{c_{ij}}$ = $(-1)^{i+j}(d)$ , where the d= determinant of the matrix after removing the i- row and j- column.

So, we have,

1. $A_{c_{11}}$ .

So, $A_{c_{11}}=(-1)^{1+1}(1\times 1-5\times (-3))$

i.e. $A_{c_{11}}=(-1)^{2}(1+15)=16$

2. $A_{c_{13}}$ .

So, $A_{c_{13}}=(-1)^{1+3}(7\times 5-1\times 8)$

i.e. $A_{c_{13}}=(-1)^{4}(35-8)=27$

3. $A_{c_{21}}$ .

So, $A_{c_{21}}=(-1)^{2+1}(7\times 1-5\times 1)$

i.e. $A_{c_{21}}=(-1)^{3}(7-5)=-2$

4. $A_{c_{22}}$ .

So, $A_{c_{22}}=(-1)^{2+2}(3\times 1-8\times 1)$

i.e. $A_{c_{22}}=(-1)^{4}(3-8)=-5$

5. $A_{c_{31}}$ .

So, $A_{c_{31}}=(-1)^{3+1}(7\times (-3)-1\times 1)$

i.e. $A_{c_{31}}=(-1)^{4}(-21-1)=-22$

Thus, we get,

Co-factor Value

$A_{c_{11}}$ 16

$A_{c_{13}}$ 27

$A_{c_{21}}$ -2

$A_{c_{22}}$ -5

$A_{c_{31}}$ -22

4 0

3 years ago

Multiply the ones 472×7​

Multiply the ones 472×7